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1800-102-2727Sulfur hexafluoride (SF₆) is also known as hexafluoro-λ6-sulphane. It is an inorganic compound and is a very stable gas. The gas is colourless and odourless. It’s a perfect example of sp³d² hybridisation in chemistry.
Let us understand how hybridisation happens in SF₆. Read on to learn how it leads to its bonding and molecular shape.
SF₆ consists of one sulfur atom and six fluorine atoms. Each fluorine atom is bonded to sulfur with single covalent bonds. In order to form these bonds, sulfur undergoes sp³d² hybridisation. Due to this hybridisation, this molecule has an octahedral molecular geometry.
We can determine the hybridisation of Sulfur hexafluoride using the simple formula:


Sulfur hexafluoride is very stable because sulfur achieves an expanded octet with 12 valence electrons. It has 6 covalent single S–F bonds. In high-voltage equipment, it is a well-known electrical insulator.
Here is a complete understanding of its hybridisation.
The atomic number of sulfur is 16.
The ground state of sulfur:
1s² 2s² 2p⁶ 3s² 3p⁴
Only two unpaired electrons → insufficient to form six bonds
Excited state configuration:
1s² 2s² 2p⁶ 3s¹ 3p³ 3d²
Six unpaired electrons → enough to form 6 bonds
Ground state vs excited state orbital diagram
sp³d² hybridisation occurs when 1 s orbital, 3 p and 2 d orbitals mix.
The result:
Each sulfur atom uses:
Result:
Geometry and bonding of SF₆
| Property | Details |
|---|---|
| Molecule | Sulfur hexafluoride (SF₆) |
| Hybridisation | sp³d² |
| Geometry | Octahedral |
| Bond angle | 90° |
| Bonding | 6 σ bonds (S–F) |
| Unhybridised Orbitals | 0 (hybridisation happens for all orbitals) |
| Sulfur valency satisfied? | Yes, by forming 6 bonds |
To determine if the Lewis structure of SF₆ is stable, we calculate the formal charge on each atom using the formula:
Formal charge = Valence electrons − (Lone pair electrons + ½ × Bonding electrons)
Sulfur (S) – central atom
Formal charge = 6 − (0 + ½ × 12) = 6 − 6 = 0
Fluorine (F) – each
Formal charge = 7 − (6 + ½ × 2) = 7 − (6 + 1) = 7 − 7 = 0
Thus, all atoms in SF₆ carry zero formal charge, confirming that the Lewis structure is stable and correct.
The sulfur in SF₆ forms 6 single covalent bonds with fluorine. sp³d² hybridisation leads to an octahedral geometry with 90° bond angles. There are no π bonds between any atom in the molecule.
Q1. Why does sulfur undergo hybridisation in SF₆?
To form 6 equivalent covalent bonds, sulfur promotes electrons and forms sp³d² hybrid orbitals.
Q2. How many σ and π bonds are present in SF₆?
There are 6 σ bonds and 0 π bonds in total.
Q3. What is the shape of SF₆?
Octahedral, due to sp³d² hybridisation.
Q4. Is SF₆ polar or non-polar?
SF₆ is non-polar, due to the cancelling of dipole, which is due to the octahedral arrangement of the molecule.
Q5. What are some uses of SF₆ in our daily lives?
SF₆ is used as an electrical insulator in high-voltage equipment and as a tracer in gas studies. It is also widely used as a protective gas in magnesium production.