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1800-102-2727In day to day life, we are witnessed with a variety of colours around us. Don’t you find this interesting? Have you even wonder how we are able to see so many colours? This all happens because of hybridisation of universal colours to get variety of colours which makes our surrounding look more beautiful and colourful.
Let’s understand this with an example:
Start with one beaker of 50 mL red water that represents the 2s orbital and three beakers, each with 50 mL blue water, that represent three 2p orbitals. Mix all four beakers then we will get 200 mL of purple water.
Why do we study hybridisation?
In methane, there should be one s-s overlapping and three -p overlapping, for formation of four C - H bonds. it is assumed that the energy, and size of these orbitals should not be same but experimentally we found that all the bond parameters of C - H bond in CH4 are same. why is this so? To figure this out, scientists had introduced a hypothetical concept which is known as hybridisation.
Table of content:
Hybridisation is defined as the concept of intermixing of atomic orbitals of similar or comparable energies of an atom to form a new set of almost same hybrid orbitals. The atomic orbitals of a similar energy level can only take part in hybridization and both fully filled and half-filled orbitals can also take part in this hypothetical process, provided they have comparable energy.
Example: Formation of SP2 hybridisation
Hybridisation = SP2
Example: Possible mixing of orbitals
Note: Orientation of hybridized orbitals should be in a way to ensure minimum repulsion between electron pairs to obtain a stable geometry.
Naming of Hybrid Orbitals: Naming can be done on the basis of the participating atomic orbitals in hybridisation.
Based on the types of orbitals involved in mixing, hybridization can be classified as
Depicting the hybridization for different steric number
Hence, hybridisation of CH4 is SP3.
where V = Number of valence electrons in the central atom
M = Number of surrounding monovalent atoms (H or halogens)
q = Charge on the ion
Example: Hybridisation of CO32-
Here central atom is .
In addition to and P orbitals, the elements in the third period have d orbitals. The energy of the 3d orbitals is similar to that of the 3s and 3p orbitals. 3d orbitals have an energy that is comparable to that of 4s and 4p orbitals. As a result, hybridization including 3s, 3p, and 3d, as well as 3d, 4s, and 4p, is possible.
Hybridisation of Pcl5 is SP3d.
Hybridisation of SF6 is SP3d2.
Q1. Calculate the hybridisation of C02 using the concept of steric number.
Answer: Steric number = Number of sigma bond pairs + Number of lone pairs
Steric number = 2 + 0 = 2 (since number of sigma bond is 2 and lone pair on C atom is 0)
For steric number equal to 2, the hybridisation comes out to be SP . Carbon dioxide (CO2) is therefore linear in geometry. The shape of CO2 is linear because there are no lone pairs affecting the orientation of the molecule.
Q2. The carbon atoms in acetylene are
A. SP
B. SP2
C. SP3
D. SP3d
Answer: A
The carbon atoms present in acetylene show sp hybridisation.
Using steric number, it can be easily calculated.
Steric number = Number of sigma bond pairs + Number of lone pairs
= 2 + 0
= 2
Hence, acetylene shows sp hybridisation.
Q3. The geometry of PlCO2 is
A. Tetrahedral
B. Trigonal planer
C. Square planer
D. Linear
Answer: B.
By using steric number calculation we can predict the hybridisation and then the geometry of PlCO2.
Steric number = Number of sigma bond pairs + Number of lone pairs
Steric number = 3 sigma bond pairs + 0 lone pairs (Having 2 pi bonds)
= 3
The hybridisation comes out to be SP2
The geometry of PlCO2 is trigonal planar. Two oxygen atoms and one chlorine atom are placed at
the corners of an equilateral triangle.
Q4. What is the hybridisation of XeF4?
A. SP
B. SP2
C. SP3
D. SP3d2
Answer: D.
Solution: Using this formula of Steric Number = , we can calculate the hybridisation of XeF4.
Number of valence electrons on the Xe atom (V) = 8
Number of surrounding monovalent atoms (M) = 4
There is no charge, q = 0
Steric Number = 6 means the hybridisation is SP3d2.
Q1. What do you mean by orbital overlapping?
Answer: When two atoms are so close together, their atomic orbitals partially overlap. This partial merging of atomic orbitals is called orbital overlapping.
Q2. What are the different d-orbitals in d subshell?
Answer: There are 5 d-orbitals in d subshell. These are
Q3. What is the difference between geometry and shape?
Answer: Geometry of a molecule is the arrangement of orbitals containing lone pair and bond pair electrons around a central atom. Shape or structure is the arrangement of atoms around the central atom excluding the lone pairs.
Q4. Why does ammonia have a distorted tetrahedral geometry in spite of having sp3 hybridisation?
Answer: Ammonia has a distorted tetrahedral geometry and trigonal pyramidal shape. This is due to the presence of the lone pair that exerts greater lone pair-bond pair repulsion on the bonding orbitals. The bond angle in ammonia is 107°, which is less than the standard 109.5° for a tetrahedral molecule having sp3.
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