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1800-102-2727A large data set is represented in a graphical or tabular form denoting the frequency of occurrence of each set of data. This observation is known as frequency distribution. For example, a class has how many cricketers, tennis players, and badminton players can be grouped into a frequency table to find out other relevant data. This grouping is known as grouped data and can be used to find out mean deviation.
In a grouped data, the class intervals are arranged in such a way that they do not have any gaps, and each class has their own frequency.
Formula: - ∑ f | X-X| / ∑ f
where, f is the value of frequency
x is the mean, calculated as (sum of all the values/number of values) = ∑ f x / ∑ f
mid points are calculated as (lower limit + upper limit) / 2.
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X =∑ f x / ∑ f = 1350/50
X= 27
Mean Deviation=∑ f | X-X| / ∑ f
= 472/50
= 9.44
Hence, mean deviation is 9.44
In ungrouped data, some of the class intervals tend to be missing with irregular frequency distributions amongst them.
Example: - Find the mean deviation of the following ungrouped data.
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Solution
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We need to find the median first. Here total entries are 7, which is an odd number.
Therefore, median = item corresponding to the value of (n+1) /2
= 8/2 = 4th item = 8
Mean deviation = ∑ f |X-Me| / N = ∑ f | D| / N
= 15/7 = 2.14