•  
agra,ahmedabad,ajmer,akola,aligarh,ambala,amravati,amritsar,aurangabad,ayodhya,bangalore,bareilly,bathinda,bhagalpur,bhilai,bhiwani,bhopal,bhubaneswar,bikaner,bilaspur,bokaro,chandigarh,chennai,coimbatore,cuttack,dehradun,delhi ncr,dhanbad,dibrugarh,durgapur,faridabad,ferozpur,gandhinagar,gaya,ghaziabad,goa,gorakhpur,greater noida,gurugram,guwahati,gwalior,haldwani,haridwar,hisar,hyderabad,indore,jabalpur,jaipur,jalandhar,jammu,jamshedpur,jhansi,jodhpur,jorhat,kaithal,kanpur,karimnagar,karnal,kashipur,khammam,kharagpur,kochi,kolhapur,kolkata,kota,kottayam,kozhikode,kurnool,kurukshetra,latur,lucknow,ludhiana,madurai,mangaluru,mathura,meerut,moradabad,mumbai,muzaffarpur,mysore,nagpur,nanded,narnaul,nashik,nellore,noida,palwal,panchkula,panipat,pathankot,patiala,patna,prayagraj,puducherry,pune,raipur,rajahmundry,ranchi,rewa,rewari,rohtak,rudrapur,saharanpur,salem,secunderabad,silchar,siliguri,sirsa,solapur,sri-ganganagar,srinagar,surat,thrissur,tinsukia,tiruchirapalli,tirupati,trivandrum,udaipur,udhampur,ujjain,vadodara,vapi,varanasi,vellore,vijayawada,visakhapatnam,warangal,yamuna-nagar
Difference between Area and Surface Area

Difference between Area and Surface Area

 

In geometry, we study mainly two dimensions: two-dimensional objects and three-dimensional objects. The two-dimensional objects are plane figures that can be represented only in two directions. In contrast, three-dimensional objects can be expressed in three directions.

Strictly speaking, if we add a third side on two-dimensional objects, then they become three-dimensional. For example, a square is a two-dimensional figure with sides, length and breadth. If we add a third side, height, then it becomes a cube. However, the third side must be of equal length as that of the other two sides to form a cube.

Area

The area is defined as the region bounded within the sides of a polygon. It is a two-dimensional quantity. It expresses the extent in a planar lamina. Lamina includes all 2D shapes, i.e. square, rectangle, triangle, circle, trapezium, etc. For example, if a body has four sides, then the inside region will denote its area.

Area of 2D shapes

Shape Area Terms
Circle π × r² r = radius of the circle
Triangle ½ × b × h b = base
h = height
Square a = length of side
Rectangle l × w l = length
w = width
Parallelogram b × h b = base
h = vertical height
Trapezium ½ (a + b) × h a and b are the length of parallel sides
h = height
Ellipse π a b a = ½ minor axis
b = ½ major axis

Surface area

The surface area is the outside area of a 3D shape. The space inside a 3D object will be its capacity, referred to as volume. Therefore, only the outside area of the surface will be considered in calculating the area.

For example, take a hollow ball. The outer shell will represent its surface area, whereas the inside hollowness will represent its volume. Thus, the surface area is dominant in 3D shapes only. Some 3D shapes include cubes, cuboids, spheres, prisms, cones, hemispheres, etc.

Surface area of 3D shapes

Shape Surface Area Terms
Cube 6a² a = length of the edge
Rectangular prism 2 (wl + hl + hw) l = length
w = width
h = height
Cylinder 2πr (r + h) r = radius of circular base
h = height of the cylinder
Cone π r (r + l) r = radius of circular base
l = slant height
Sphere 4πr² r = radius of sphere
Hemisphere 3πr² r = radius of hemisphere

Difference between area and surface area

Area Surface Area
It is a two-dimensional property. It is a three-dimensional property.
It is the space occupied by lines of a shape. It is the outer area of any body, not the inside space.
Examples of shapes having area are - square, rectangle, triangle, circle, etc. Examples of shapes having surface area are cubes, cuboids, prisms, cones, etc.
We can calculate area by knowing the sides of any 2D shape. We can calculate the surface area if we know all the sides of any shape.
Real life applications of area include finding the quantity of paint required to paint a wall, sheet of paper required to draw a book, etc. Real life applications include finding the quantity to paint a matchbox, gift wrap required to wrap a book, etc.

Example 1: Find the area and surface area of a circular park whose radius is 9 m.

Solution:

From the formula, we know,

Area of circle = π r²

A = 22/7 x 9 x 9

A = 254.57 sq.m.

Also, we know the surface area of a sphere = 4πr²

A = 4 x 22/7 x 92 = 1018.28 sq.m.

Example 2: Find the area of the cone, whose radius is 7 cm and height is 5 cm.

Solution:

We know, the area of cone = π r (r + l)

Where, l = slant height of the cone, and is given by:

l = √(7² + 5²) = √49 + 25 = 8.6 cm

Therefore, Area = (22/7) × 7 (7 + 8.6)

= 22/7 x 7 x 15.6 = 343.2 cm²

NEET Related Links

NEET Exam 

NEET  Exam Dates

NEET  Exam pattern

NEET  Syllabus

NEET  Eligibility Criteria

NEET  Application

NEET UG Counselling

NEET FAQ

NEET UG Result

NEET  Cut Off

JEE MAIN Related Links

JEE Main 

JEE Main Rank Predictor 

JEE Main College Predictor 

JEE Main  Exam Dates

JEE Main  Exam pattern

JEE Main  Application

JEE Main  Eligibility Criteria

JEE Main  Syllabus

JEE Main  Physics Syllabus

JEE Main  Maths Syllabus

JEE Main  Chemistry Syllabus

JEE Main  Admit Card

JEE Main  Counselling

JEE Main marks vs rank vs percentile

JEE Advanced Related Links

JEE Advanced  Exam Dates

JEE Advanced  Application

JEE Advanced  Eligibility Criteria

JEE Advanced  Syllabus

JEE Advanced  Maths Syllabus

JEE Advanced  Physics Syllabus

JEE Advanced  Chemistry Syllabus

JEE Advanced Exam Result

JEE Advanced Exam Dates

JEE Advanced Registration Dates

CUET Related Links

CUET  Eligibility Criteria

CUET  Admit Card

CUET  Exam Pattern

CUET  FAQs

CUET  Counselling

CUET  Syllabus

CUET  Result

CUET  Answer Key

CUET  Preparation

CUET CUTOFF

CUET  Application Form

Important Topics

Talk to our expert
Resend OTP Timer =
By submitting up, I agree to receive all the Whatsapp communication on my registered number and Aakash terms and conditions and privacy policy