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Xenon Dioxide Difluoride (XeO₂F₂) is also known as difluoro(dioxo)xenon. It has one xenon atom bonded to two fluorine atoms and two oxygen atoms. It’s a good example of sp³d hybridisation in inorganic chemistry. The compound also expands its octet.
Let us understand how hybridisation happens in XeO₂F₂. Read on to learn how it leads to its bonding and molecular shape.
Xenon Dioxide Difluoride consists of one central xenon atom, which is bonded to fluorine atoms and oxygen atoms. In all, it also has one lone pair of electrons. In order to form these bonds and follow the principle of expanded octet, xenon undergoes sp3d hybridisation.
XeO₂F₂ has a see-saw shape. The lone pairs take up equatorial positions, leading the fluorine atoms to take the axial positions. The VSEPR Theory explains all this structure.
Here is a complete understanding of its hybridisation.
Atomic number of xenon: 54
The ground state of xenon :
1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶
Only has zero unpaired electron → insufficient to form four bonds
Excited state configuration:
1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p3 5d3
Now, six unpaired electrons → enough to form bonds
And, now we can have space for lone pair also
Ground state vs excited state orbital diagram
sp³d hybridisation occurs when 1 s orbital, 3 p orbitals, and 1 d orbital mix to form equivalent hybrid orbitals.
The result:
→ 5 sp³d hybrid orbitals on the xenon atom
→ These accommodate lone pairs and are used to form bonds between atoms.
The xenon atom uses:
Result:
Geometry of Xenon Dioxide Difluoride
|
Property |
Details |
|
Molecule |
Xenon Dioxide Difluoride (XeO₂F₂) |
|
Hybridisation |
sp³d |
|
Geometry |
Trigonal Bipyramidal (distorted) |
|
Bond angle |
<120° (equatorially) and <90° (axially) |
|
Bonding |
4 σ bonds (2 Xe–F, 2 Xe–O) + 2 π bonds (Xe=O) |
|
Unhybridised Orbitals |
0 (all involved in hybridisation) |
|
Xenon valency satisfied? |
Yes, by having expanded octet with 10 electrons around it |
To determine if the Lewis structure of XeO₂F₂ is stable, we calculate the formal charge on each atom using the formula:
Formal charge = Valence electrons – (Lone pair electrons + ½ × Bonding electrons)
Step-by-step for each atom:
Xenon (Xe) :
Formal charge = 8 – (2 + ½×12) = 8 – (2 + 6) = 8 – (8) = 0
Oxygen (O) – each
Formal charge = 6 – (4 + ½×4) = 6 – (4 + 2) = 6 – (6) = 0
Fluorine (F) – each
Formal charge = 7 – (6 + ½×2) = 7 – (6 + 1) = 7 – (7) = 0
Thus, all atoms in XeO₂F₂ have zero formal charge, which concludes and confirms that the Lewis structure is stable and correct.
Xenon in XeO₂F₂ forms 6 bonds: 2 with fluorine and 4 with oxygen (2 σ and 2 π). XeO₂F₂ has a distorted trigonal bipyramidal geometry and ends up having a see-saw-like structure.
Q1. Why does xenon undergo hybridisation in XeO₂F₂?
To form 4 single bonds with F and O and also accommodate 1 lone pair, xenon forms multiple bonds, promotes electrons, and uses d orbitals for bonding.
Q2. How many σ and π bonds are present in XeO₂F₂?
There are 4 σ bonds and 2 π bonds in total.
Q3. What is the shape of Xenon Dioxide Difluoride?
Distorted trigonal bipyramidal (See-saw), due to the presence of a lone pair.
Q4. Is XeO₂F₂ polar or non-polar?
Polar, as the molecule has asymmetrical distribution of charge due to lone pairs.
Q5. What are some uses of Xenon Dioxide Difluoride in our daily lives?
Xenon Dioxide Difluoride, under specific conditions, can be synthesized by the reaction of xenon with oxygen difluoride (OF₂).