Call Now
1800-102-2727Sulfur Dioxide (SO₂) is also known as sulfurous anhydride. It is a molecule with a bent shape and is part of the main pollutants in the atmosphere. It is the toxic component in acid rains. It’s a good example of sp² hybridisation in inorganic chemistry.
Let us understand how hybridisation happens in SO₂. Read on to learn how it leads to its bonding and molecular shape.
Sulfur Dioxide consists of one sulfur atom and two oxygen atoms. Each of the oxygen atoms is bonded to the sulfur atom. In all, the molecule also contains a lone pair of electrons. In order to form these bonds and satisfy the octet rule, sulfur undergoes sp² hybridisation.
We can determine the hybridisation of sulphur dioxide using the simple formula:
Step-by-step calculation:
Interpretation:
The sulfur dioxide’s hybridisation has a resonant structure as it has a delocalised π system over the two S–O bonds, making both bonds equivalent. SO₂ also contains a lone pair of electrons.
Here is a complete understanding of its hybridisation.
The atomic number of sulfur is 16.
The ground state of sulfur :
1s² 2s² 2p⁶ 3s² 3p⁴
Only two unpaired electrons → insufficient to form two required double bonds and also satisfy the octet rule
Excited state configuration:
1s² 2s² 2p⁶ 3s¹ 3p³ 3d¹
Four unpaired electrons → enough to form two bonds with O which are strong, and along with that also undergo resonance
sp² hybridisation occurs when 1 s orbital and 2 p orbitals mix.
The result:
→ 3 sp² hybrid orbitals on the sulfur atom
→ The remaining 1 unhybridised p orbital stays available for π bonding
The sulfur atom in SO₂ undergoes sp² hybridisation, resulting in three sp² hybrid orbitals and one unhybridised p orbital.
Result:
Hybridisation type: sp²
Bond angle: ~119° (caused by repulsion between lone pair and bonding pairs)
Geometry: Bent
| Property | Details |
|---|---|
| Molecule | Sulfur Dioxide (SO₂) |
| Hybridisation | sp² |
| Geometry | Bent |
| Bond angle | ~119° |
| Bonding | 2 σ bonds (S–O), π bond (delocalised over both single bonds) |
| Unhybridised Orbitals | 1 (on sulfur for π bonding) |
| Sulfur valency satisfied? | Yes, by forming 2 bonds and having 1 lone pair of electrons |
To determine if the Lewis structure of SO₂ is stable, we calculate the formal charge on each atom using the formula:
Formal charge = Valence electrons – (Lone pair electrons + ½ × Bonding electrons)
Step-by-step for each atom:
Sulfur (S) – central atom
Formal charge = 6 – (2 + ½×8) = 6 – (2 + 4) = 6 – (6) = 0
Oxygen (O) – each
Formal charge = 6 – (4 + ½×4) = 6 – (4 + 2) = 6 – (6) = 0
Thus, all atoms in SO₂ carry zero formal charge, confirming that the Lewis structure is stable and correct.
The sulfur in SO₂ forms 2 bonds with oxygen and shares a π bond (delocalised) with the same atoms. sp² hybridisation leads to a bent shape and ~119° bond angles. The change in bond angle is because of the repulsion between lone pair and bonding pairs.
Q1. Why does sulfur undergo hybridisation in SO₂?
To form stable covalent bonds and also hold lone pair, sulfur promotes an electron and mixes orbitals to form hybrid orbitals.
Q2. How many σ and π bonds are present in SO₂?
There are 2 σ bonds and π (delocalised) bond in total.
Q3. What is the shape of SO₂?
Bent, due to repulsion between lone pair and bonding pairs.
Q4. Is SO₂ polar or non-polar?
Sulfur Dioxide is polar, the bond dipoles do not cancel out because of the bent molecular shape.