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1800-102-2727Phosphorus trichloride (PCl₃) is a molecule with a trigonal pyramidal structure. It’s an excellent example of sp³ hybridisation in inorganic chemistry.
Let us understand how hybridisation happens in PCl₃. Read on to learn how it leads to its bonding and molecular shape.
Phosphorus trichloride consists of one phosphorus atom and three chlorine atoms. Each chlorine atom is bonded to phosphorus. In order to form these bonds, phosphorus undergoes sp³ hybridisation.
We can determine the hybridisation of phosphorus trichloride using the simple formula:

Step-by-step calculation:

Interpretation:
3 σ bonds + 1 lone pair → 4 regions of electron density → sp³ hybridisation
Phosphorus trichloride consists of one pair of lone electrons and has a trigonal pyramidal molecular shape. It has 3 covalent single P–Cl bonds.
Here is a complete understanding of its hybridisation.
The atomic number of phosphorus is 15.
The ground state of phosphorus :
1s² 2s² 2p⁶ 3s² 3p³
Phosphorus has three unpaired electrons in 3p orbitals, enough to form 3 σ bonds; the lone pair remains in the 3s orbital.
Excited state configuration: Since PCl₃ can already form 3 bonds using the 3 unpaired electrons of p orbital, and the remaining lone pair will be in the s orbitals, it does not need any excited state.
sp³ hybridisation occurs when 1 s orbital and 3 p orbitals mix.
The result:
→ 4 sp³ hybrid orbitals on phosphorus atom
→ 3 sp³ hybrid orbitals used for σ bonding with chlorine atoms
→ 1 sp³ hybrid orbital has the lone pair of electrons
Each phosphorus atom uses:
Result:
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Geometry and bonding of PCl₃
| Property | Details |
|---|---|
| Molecule | Phosphorus trichloride (PCl₃) |
| Hybridisation | sp³ |
| Geometry | Trigonal pyramidal |
| Bond angle | ~107° |
| Bonding | 3 σ bonds (P–Cl), 1 LP (lone pair) |
| Unhybridised Orbitals | 0 (hybridisation happens for all the valence orbitals) |
| Phosphorus valency satisfied? | Yes, by forming 3 bonds and having 1 lone pair of electron |
To determine if the Lewis structure of PCl₃ is stable, we calculate the formal charge on each atom using the formula:
Formal charge = Valence electrons – (Lone pair electrons + ½ × Bonding electrons)
Step-by-step for each atom:
Phosphorus (P) – central atom
Formal charge = 5 – (2 + ½×6) = 5 – (2 + 3) = 0
Chlorine (Cl) – each
Formal charge = 7 – (6 + ½×2) = 7 – (6 + 1) = 0
Thus, all atoms in PCl₃ carry zero formal charge, confirming that the Lewis structure is stable and correct.
The phosphorus in PCl₃ forms 3 single covalent bonds with chlorine and has one lone pair of electron. sp³ hybridisation leads to a trigonal pyramidal shape with ~107° bond angles. The decrease in bond angle is because of the presence of a lone pair.
Q1. Why does Phosphorus undergo hybridisation in PCl₃?
To form 3 covalent bonds and arrange electrons such that minimal repulsion is present, phosphorus mixes orbitals to form hybrid orbitals.
Q2. How many σ and π bonds are present in PCl₃?
There are 3 σ bonds and 0 π bonds in total.
Q3. What is the shape of PCl₃?
Trigonal pyramidal, due to sp³ hybridisation and presence of lone pair.
Q4. Is PCl₃ polar or non-polar?
PCl₃ is polar, due to the asymmetrical electron distribution, as there is presence of lone pair of electron.
Q5. What are some uses of PCl₃ in our daily lives?
PCl₃ is commercially used as the chlorinating agent in chemical synthesis. It is also used in manufacturing organophosphorus compounds, pesticides, etc.