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1800-102-2727Nitrogen Dioxide (NO₂) is also known as the dioxide of nitrogen. It is a free radical with a bent shape and is reddish brown in colour. It is also a toxic gas. It’s a classic example of sp² hybridisation in inorganic chemistry.
Let us understand how hybridisation happens in NO₂. Read on to learn how it leads to its bonding and molecular shape.
Nitrogen Dioxide consists of one nitrogen atom and two oxygen atoms. Each of the oxygen atoms is bonded to the nitrogen atom. In all, the molecule also contains an unpaired electron. In order to form these bonds, nitrogen undergoes sp² hybridisation.
Nitrogen Dioxide’s hybridisation can be easily determined by the number of electron regions. The Lewis structure of the NO₂ also has an unpaired electron, which makes it a part of the odd-electron molecules’ family.
Here is a complete understanding of its hybridisation.
The atomic number of nitrogen is 7.
The ground state of nitrogen :
1s² 2s² 2p³
This gives nitrogen three unpaired electrons, which are enough to form two sigma bonds (with oxygen atoms) and still have one unpaired electron.
sp² hybridisation occurs when 1 s orbital and 2 p orbitals mix.
The result:
→ 3 sp² hybrid orbitals on the nitrogen atom
→ The remaining 1 unhybridised p orbital stays available for π bonding
→ The one remaining electron, which is going to remain unpaired, will contribute towards the paramagnetic nature of NO₂
Each nitrogen atom uses:
Result:
Geometry and bonding of Nitrogen Dioxide
| Property | Details |
|---|---|
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|
| Molecule | Nitrogen Dioxide (NO₂) |
| Hybridisation | sp² |
| Geometry | Bent |
| Bond angle | ~134° |
| Bonding | 2 σ bonds (N–O), 1 π bond (delocalised) |
| Unhybridised Orbitals | 1 (on nitrogen for π bonding) |
| Unpaired Electron | Yes (paramagnetic nature) |
To determine if the Lewis structure of NO₂ is stable, we calculate the formal charge on each atom using the formula:
Formal charge = Valence electrons – (Lone pair electrons + ½ × Bonding electrons)
Step-by-step for each atom:
Nitrogen (N) – central atom
Formal charge = 5 – (2 + ½×6) = 5 – (2 + 3) = 0
Oxygen (O) – doubly-bonded
Formal charge = 6 – (4 + ½×4) = 6 – (4 + 2) = 0
Oxygen (O) – singly-bonded
Formal charge = 6 – (6 + ½×2) = 6 – (6 + 1) = –1
Thus, atoms in NO₂ carry formal charge of Nitrogen (0), Doubly-bonded oxygen (0) and singly bonded oxygen (-1), and since the molecule has resonance hybrid the negative charge is then delocalised over both atoms of oxygen.
The nitrogen in NO₂ forms 2 bonds with oxygen and shares a π bond (delocalised) with the same atoms. sp² hybridisation leads to a bent shape and slightly greater than 120° in ideal sp², but in NO₂ it is actually ~134°. The change in bond angle is because of the repulsion between unpaired and lone pair electrons.
Q1. How many σ and π bonds are present in NO₂?
There are 2 σ bonds and 1 π (delocalised) bond in total.
Q2. Is NO₂ polar or non-polar?
Nitrogen dioxide is polar. The molecule has a bent shape and a significant electronegativity difference between nitrogen and oxygen. Thus, it creates a net dipole moment.
Q3. What is the shape of NO₂?
Bent, due to repulsion between lone pair and unpaired electrons.