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1800-102-2727Water (H₂O) is also known as dihydrogen monoxide. Water, as a molecule, is quite simple. It has covalent bonds with two hydrogen atoms. It’s an example of sp³ hybridisation, which is the main reason it has many unique properties.
Let us understand how hybridisation happens in H₂O. Read on to learn how it leads to its bonding and molecular shape.
Water consists of one oxygen atom and two hydrogen atoms. Apart from this, oxygen also has two lone pairs. Each hydrogen atom is bonded to oxygen, covalently. In order to accommodate the four electron density oxygen has, it undergoes sp³ hybridisation.
We can determine the hybridisation of water using the simple formula:

Step-by-step calculation:

Interpretation:
Hybridisation number = 4, which corresponds to sp³ hybridisation.
Water has a tetrahedral geometry, in accordance with its hybridisation. But in reality, the lone pairs end up taking more space when compared to bonded pairs, which results in a bent shape of the molecule.
Here is a complete understanding of its hybridisation.
The atomic number of oxygen is 8.
The ground state of oxygen :
1s² 2s² 2p⁴
Only two unpaired electrons → sufficient to form two bonds, but lone pair arrangement and geometry are still required
Excited state configuration:
1s² 2s² 2pₓ² 2pᵧ¹ 2pz¹
Lone pairs remaining → orbitals will now be hybridised for correct geometry
Ground state vs excited state orbital diagram
sp³ hybridisation occurs when 1 s orbital and 3 p orbitals mix.
The result:
→ 4 sp³ hybrid orbitals
→ 2 of the orbitals will be used for σ bonding with hydrogen, left will be occupied with lone pairs
Each oxygen uses:
Result:
Geometry and bonding of water
| Property | Details |
|---|---|
| Molecule | Water (H₂O) |
| Hybridisation | sp³ |
| Geometry | Bent |
| Bond angle | 104.5° |
| Bonding | 2 σ bonds (O–H), 2 lone pairs |
| Unhybridised Orbitals | 0 |
| Oxygen valency satisfied? | Yes, by forming 2 bonds with each hydrogen atom and having 2 LP |
To determine if the Lewis structure of H₂O is stable, we calculate the formal charge on each atom using the formula:
Formal charge = Valence electrons – (Lone pair electrons + ½ × Bonding electrons)
Step-by-step for each atom:
Oxygen (O)
Formal charge = 6 – (4 + ½×4) = 6 – (4 + 2) = 0
Hydrogen (H) – each
Formal charge = 1 – (0 + ½×2) = 1 – 1 = 0
Thus, all atoms in H₂O carry zero formal charge, confirming that the Lewis structure is stable and correct.
The oxygen in H₂O bonds with hydrogen (2 σ) and also has lone pairs. sp³ hybridisation leads to a tetrahedral shape, but due to lone pair repulsion, the angles get compressed to 104.5°, giving it a bent molecular shape (similar to V-shape).
Q1. Why does H₂O have V-shaped geometry?
Oxygen in water has two lone pairs, and since the repulsion between two lone pairs in a system is highest, it affects the O-H bonds and causes them to become compressed, resulting in a bent shape.
Q2. How many σ and π bonds are present in H₂O?
There are 2 σ bonds and 0 π bonds in total.
Q3. What is the shape of water?
Bent, due to lone pair repulsion.
Q4. Is H₂O polar or non-polar?
Water is polar, as the dipoles do not cancel out due to high electronegativity of oxygen.
Q5. What are some uses of water in our lives?
Water is the most essential part of the living and nonliving realm. It has vast usages which include regulating Earth's atmosphere, etc. It is also known as a universal solvent.