Call Now
1800-102-2727Chlorine Trifluoride (ClF₃) has one chlorine and three fluorine atoms. It is an interhalogen compound and undergoes sp³d hybridisation, attaining a T-shaped molecular structure.
Let us understand how hybridisation happens in ClF₃. Read on to learn how it leads to its bonding and molecular shape.
Chlorine Trifluoride consists of one central chlorine atom, which is bonded to fluorine atoms and has two lone pairs left. Since chlorine has 5 sets of electrons (3 bonding pairs + 2 lone pairs), it undergoes sp³d hybridisation and follows the principle of expanded octet.
We can determine the hybridisation of chlorine trifluoride using the simple formula:

Step-by-step calculation:

Interpretation:
Hybridisation number = 5, which corresponds to sp³d hybridisation.
ClF₃ has a trigonal bipyramidal electron geometry, but it acquires a T-shaped structure. The lone pairs take up equatorial positions, which results in greater repulsion.
Here is a complete understanding of its hybridisation.
The atomic number of chlorine is 17.
The ground state of chlorine:
1s² 2s² 2p⁶ 3s² 3p⁵
Only has one unpaired electron → insufficient to form 3 bonds
Excited state configuration:
1s² 2s² 2p⁶ 3s² 3p⁴ 3d¹
Now, three unpaired electrons → enough to form 3 Cl–F bonds
Also includes lone pairs → total of 5 regions of electron density
Ground state vs excited state orbital diagram of Cl
sp³d hybridisation occurs when 1 s orbital, 3 p orbitals, and 1 d orbital mix to form equivalent hybrid orbitals.
The result:
→ 5 sp³d hybrid orbitals are formed
→ These accommodate lone pairs and are used to form bonds between atoms.
Result:
Geometry and bonding of Chlorine Trifluoride
| Property | Details |
|---|---|
| Molecule | Chlorine Trifluoride (ClF₃) |
| Hybridisation | sp³d |
| Geometry | T-shaped |
| Bond angle | 175° and ~87.5° |
| Bonding | 3 σ bonds (Cl–F), 2 lone pairs |
| Unhybridised Orbitals | d-orbitals are involved |
| Chlorine valency satisfied? | Yes, expanded octet with 10 electrons around Cl |
| Boiling Point | 11.75 °C |
| Melting Point | −76.34 °C |
To determine if the Lewis structure of ClF₃ is stable, we calculate the formal charge on each atom using the formula:
Formal charge = Valence electrons – (Lone pair electrons + ½ × Bonding electrons)
Step-by-step for each atom:
Chlorine (Cl) :
Formal charge = 7 – (4 + ½×6) = 7 – (4 + 3) = 0
Fluorine (F) – each
Formal charge = 7 – (6 + 1) = 0
Thus, all atoms in ClF₃ carry zero formal charge, which confirms that the Lewis structure is stable and correct.
Chlorine in ClF₃ forms 3 σ bonds, and ends up with 2 lone pairs. The molecule follows the concept of an expanded octet and thus ends up undergoing sp³d hybridisation. ClF₃ has T-shaped molecular geometry and bond angles of 175° and ~87.5° (due to lone pair repulsion).
Q1. Why does chlorine undergo hybridisation in ClF₃?
To form 3 three bonds with fluorine and also accommodate 2 lone pairs, chlorine hybridises into sp³d orbitals.
Q2. How many σ and π bonds are present in ClF₃?
There are 3 σ bonds and 0 π bonds in total.
Q3. What is the shape of Chlorine Trifluoride?
T-shaped, due to 3 bonding pairs and 2 lone pairs.
Q4. Is ClF₃ polar or non-polar?
Polar, because the T-shape of ClF₃ causes an uneven distribution of charge.
Q5. What are some uses of Chlorine Trifluoride in our daily lives?
ClF₃ is highly reactive. It is advised to be handled with care and is used for nuclear fuel processing and rocket propellants. Chlorine Trifluoride is also used as a fluorinating agent.