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1800-102-2727The parent hydrocarbon with a cyclic shape and aromatic nature? Yes, it is benzene. This cyclic compound stands out for its stability, symmetry, and unique bonding structure. With the molecular formula C₆H₆, benzene features a six-carbon ring. Each carbon atom forms alternating single and double bonds with its neighbours, creating resonance.
To go deeper into the atoms and structure, let’s understand the hybridisation of benzene in detail.
At the molecular level, each carbon in benzene undergoes sp² hybridisation. This allows for the formation of 3 sigma (σ) bonds and a delocalised π-electron cloud above and below the ring, which marks aromaticity.
The result? A perfectly planar, hexagonal ring with equal bond lengths and enhanced stability.
The following steps explain the mechanism of the hybridisation of benzene:
The electronic configuration of Benzene is:
1s2 2s2 2p2
This ground-state configuration is as follows:
1s2 2s2 2px1 2py1 2pz0
The electron excitation causes the electron to move to the empty 2pz orbital. The new electronic configuration becomes:
1s2 2s1 2px1 2py1 2pz1
Now, there are four non-bonded electrons.
In benzene, the following bond formation takes place:
Three atomic orbitals from each carbon (2s, 2px, and 2py) combine to form three sp² hybrid orbitals, which participate in forming three sigma (σ) bonds (two with neighbouring carbon atoms and one with hydrogen).
The remaining unhybridised 2pz orbital on each carbon lies perpendicular to the plane of the ring. These orbitals overlap sideways (laterally) to create π (pi) bonds. The continuous overlap of these p orbitals around the ring gives rise to a delocalised π-electron cloud. It is responsible for the resonance and stability of benzene. So, along with three sigma bonds, each carbon also contributes to a delocalised pi bonding system across the ring.
Hybridisation of benzene
| Property | Description |
|---|---|
| Hybridisation (C atom) | sp² |
| Shape | Planar Hexagonal Ring |
| Bond Angle | 120° |
| Bonding Type | 3 σ bonds per carbon (2 C–C and 1 C–H) + delocalised π bonds |
| Orbital Overlaps | s–s (C–H), p–p (C–C), π (sideways overlap of unhybridised 2pz orbitals) |
| Delocalisation | Present (π electrons spread above and below the ring) |
| Aromaticity | Yes (follows Hückel’s Rule with 6 π electrons) |
| Stability | Highly stable due to resonance and delocalised electrons |
| Polarity | Non-polar (symmetrical structure cancels dipole moments) |
Benzene (C₆H₆) is a cyclic, planar, and aromatic hydrocarbon, with each carbon atom undergoing sp² hybridisation. It has delocalised π electrons that give rise to resonance, which explains benzene’s exceptional stability and uniform bond lengths. Though structurally fascinating, benzene is also carcinogenic, so it must be handled with care in practical applications.
Q1. What is the significance of benzene hybridisation?
Benzene’s sp² hybridisation explains its planar structure, equal bond angles, and aromatic stability. Understanding this hybridisation is essential in organic synthesis, drug design, and material science. Its molecular geometry and electron delocalisation influence reactivity.
Q2. What types of reactions are seen in benzene?
Benzene primarily undergoes electrophilic aromatic substitution (EAS) reactions. These include nitration, halogenation, sulfonation, and Friedel–Crafts reactions. Its aromatic ring is highly stable, so benzene resists addition reactions. It favours substitution to preserve its aromaticity.
Q3. What is the geometry of benzene?
The geometry is planar hexagonal, and the bond angle of benzene is 120°.
Q4. What is the result of benzene hydrogenation?
The catalytic addition of hydrogen to benzene gives Cyclohexane as the product.