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1800-102-2727A carbocation is a molecule with three bonds and a positively charged carbon atom. A carbocation is a general term for them. It was previously known as carbonium ion. Any even-electron cation with a large positive charge on the carbon atom is now known as a carbocation.
Because of the incomplete octet, the carbon cations are extremely reactive and unstable. Carbocations lack eight electrons and so do not satisfy the octet rule.
A carbocation is commonly seen in reactions, elimination reactions, and other chemical reactions.
Table of contents
Carbocation
It is a reaction intermediate that contains three bond pairs and a positive charge on it. Therefore, it has a total of six valence electrons. Carbocations can be (methyl carbocation) or sp hybridized (vinyl carbocation).
Classification of carbocations
The number of carbon groups bound to the carbon atom of the carbocation determines the name of the carbocation. The number of carbon atoms connected to the carbocation determines whether it is primary, secondary, or tertiary:
There are some other examples of carbocations which are given as:
Formation of Carbocation
There are two fundamental steps involved in the formation of a carbocation:
Heterolytic Bond Cleavage
When the bond between carbon and the atom bound to it is heterolytically cleaved, the leaving group leaves with the shared pair of electrons, and leaves the carbon as a carbocation which is an electron-deficient species.
It is formed as an intermediate in many organic reactions.
The lower the activation energy, the greater the chances of bond cleavage or formation of a more stable carbocation.
Electrophilic Addition
In electrophilic addition, an electrophile attacks an unsaturated point (double or triple bond), the pi bond breaks, and carbocation forms. The lower the activation energy, the faster the addition, and the more stable the carbocations are.
Stability of carbocation
The factors affecting the stability of carbocations are as follows:
Overall Stability order of Carbocations
[1]
[2]
Important points for the stability order of carbocations
Example: The seven-membered aromatic tropylium cation, containing six pi electrons is the most stable in the given order followed by cyclopropenyl carbocation (double bond in conjugation with a positive charge) having two pi electrons.
().
Bredt’s Rule
Small ring bicyclic molecules cannot have carbocations or double bonds at the bridgehead position because they are hybridized.
If one or two-membered bridges are there in the bicyclic molecule, then these are known as small ring bicyclic compounds.
The bridgehead carbons in the norbornane molecule are shown in the following figure:
Example:
| Possibility 1 | Possibility 2 |
|
In the molecule, a positive charge on a bridgehead carbon makes the system much more strained and unstable Can not be formed |
In the given molecule, a positive charge is not present on the bridgehead carbon, so it is comparatively stable carbocation Can be formed |
Stability of Alicyclic Cations
Each hybridized carbon atom has some bond angles associated with it. When that bond angle is not attained, the molecule gets an angular strain. For the hybridized carbon of the carbocation, the expected bond angle is
.
Angular strain is the result of deviation from ideal bond angles caused by inherent structural constraints (such as ring size).
|
Carbocation Molecule |
Expected Bond Angle |
Actual Bond Angle |
Angular Strain |
| 0 | |||
Bond angle and strain involved for various carbocations
The cyclic rings with the least angular strain are the most stable. Thus, the order of stability of carbocations is
Rearrangement of Carbocation
Whenever a carbocation intermediate is formed in a reaction, it may rearrange to gain stability. Only those carbocations which can produce a more stable form of carbocation will rearrange.
There are five types of possible rearrangements.
In this case, a methyl group shifts with a pair of electrons to the adjacent positively charged carbon to form a more stable tertiary carbocation. This kind of shift is known as a 1,2-methyl shift.
[3]
In this case, a phenyl group can shift with a pair of electrons to the adjacent positively charged carbon to form a more stable carbocation. This kind of shift is known as a 1,2-phenyl shift.
Ring expansion is also a type of rearrangement.
The trick for ring expansion/contraction
Here, the carbon having the positive charge is taken as the alpha carbon (just to remember the trick).
Example:
1.
2.
Ring contraction will only happen if a more stable carbocation is formed after contraction. A similar trick is followed in making a stable carbocation.
Example:
A cyclopropyl methyl carbocation is formed, which is highly stable.
Migratory aptitude
The tendency of an atom or group of atoms to migrate with their bonded electrons from one atom to another is called migratory aptitude of that atom or group of atoms.
Migratory Tendency of groups in the rearrangement of Carbocation is as follows:
Practice Problems
Q. 1. Which of the following is/are the most stable carbocation(s) ?
Answer: D
Solution:
In option (A), the molecule has a primary allylic carbocation.
In option (B), the molecule has a tertiary carbocation. However, it is not in conjugation with the double bond.
In option (C), the molecule has a tertiary carbocation, which is also allylic.
In option (D), the molecule has a tertiary carbocation with two allylic groups. Hence, it is most stable.
Thus, option (D) is the correct answer.
Q. 2. Why Cyclopropylmethyl cation is more stable than benzyl cation?
Solution:
Each carbon atom of the ring of this carbocation is hybridized. Thus, the bond angle should be
28’. However, due to the cyclic ring, the bond angle is reduced to a greater extent. But in order to somewhat minimize this angular strain, the carbon-carbon bonds (cyclic ring) formed by the hybrid orbitals are off-centered bulging bonds.
The hydrogens of the carbocation are perpendicular to the plane of the vacant orbital. Since the empty p-orbital of the carbocation and the hybrid orbitals (involved in carbon-carbon bonds) of the cyclopropyl ring are in the same plane, conjugation between the bent orbital of the cyclopropyl ring and vacant atomic orbital of the carbocation is observed and hence the carbocation is stabilized through the conjugation.
Q. 3. Which of the following structures is the most stable carbocation?
Answer: A
Solution:
In option (A), all the three rings A, B, and C are involved in conjugation with carbocation.
In option (B), let us denote the carbon having a positive charge as X. Now, this is in conjugation with the double bonds present in ring B, and the pi electrons of ring B are in conjugation with ring A. Thus, only two rings A and B participate in conjugation in the whole system.
In option (c), the benzyl cation (also, a tertiary cation) is present in conjugation with two rings. Thus, only two rings B and C participate in conjugation in the whole system.
In option (d), only one ring C is in conjugation with the carbocation in the whole system.
Thus, option (A) is the correct answer.
Q. 4. Arrange the following carbocations in decreasing order of their stability.
Solution:
In structure (I), the positive charge is on the bridgehead carbon atom. Thus, it disobeys Bredt’s rule. So, it is the least stable.
In structure (II), the carbocation is a secondary carbocation that is more stable than the primary.
In structure (III), the carbocation is a tertiary carbocation. So, it is the most stable.
In structure (IV), the carbocation is a primary carbocation.
Thus, the correct order of stability of carbocations is as follows: (iii) > (ii) > (iv) > (i).
Q. 5. In which of the following pairs the second ion is more stable than the first one?
Answer: B and C
Solution:
The stability order for the species is: Aromatic > Non-aromatic > Anti-aromatic
In option (A), the first one is aromatic and the second is anti-aromatic.
In option (B), the first one is non-aromatic and the second is aromatic.
In option (C), the first one is anti-aromatic and the second is aromatic.
In option (D), the positive charge on carbon in the first compound is stabilized by the
+M effect of the oxygen atom of −OH. Thus it is more stable than the tertiary
carbocation in the second one.
Thus, options (B) and (C) are correct answers.
Q. 6. Rearrange (if applicable) the following carbocation into the more stable form.
Solution:
Hydride shift can occur either from the left or the right side. The possible ways of rearranging the carbocation are as follows:
A positive charge on the carbon is more stabilized when the −OH group is attached to it as it completes the octet of the carbocation (due to the formation of oxonium ion).
Hence, hydride shift takes place from the left carbon atom forming a more stable carbocation. So, the first possibility is preferred.
Frequently Asked Questions
Q.1. What is the shape of methyl carbocation?
Answer: Methyl carbocation is a hybridized cation having a trigonal planar shape.
Q. 2. Give one name reaction which involves the carbocation intermediate formation.
Answer: In Wagner-Meerwein rearrangement carbocation is formed as an intermediate.
Q. 3. Why is tertiary carbocation more stable than secondary and primary carbocation?
Answer: In tertiary carbocation, there are more alpha hydrogens than in secondary and primary carbocation, so by hyperconjugation and the inductive effect it is generally more stable.
Stability order: Tertiary > Secondary > Primary
Related Topics
| Chlorination | Friedel-crafts reaction |
| Electrophilic Aromatic Substitution reactions of benzene | Alkanes |
| Chemical Reactions of Alkynes | Toluene |