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# RD Sharma Solutions for Class 10 Mathematics Chapter 16: Surface Areas and Volumes

Students came across solid figures like cuboids, cubes, spheres, and cones in the previous academic sessions. Almost all the structures (specifically speaking containers) that we come across in our day to day life are either these basic figures or a combination of them. As the name suggests, chapter 16-Surface Areas and Volumes, deals with calculating the volumes and the surface areas of these basic and compound figures. Thus this chapter holds great value in solving day-to-day problems.

The first section of the chapter deals with the surface area of compound solid figures. In order to solve such questions, students must be thorough with the following basic formulas:

 SOLID FIGURE SURFACE AREA Cube 6a² Cuboids 2 (ab + ah + bh) Sphere 4 πr² cone πr(r+l) cylinder 2 πr(r+h)

Furthermore, Chapter 16-Surface Areas and Volumes deals with the calculation of volumes for compound figures. This can be achieved by dividing the figures into basic figures and then adding up their volumes. Finally, the chapter elaborates on calculating the dimensions of new figures created by moulding an older figure. This can be done by calculating the volume of the old figure. The new figure will have the same volume, and hence its dimensions can be calculated by equating their respective formula with the area calculated.

Chapter 16- Surface Areas and Volumes concludes by introducing a new figure to the students, a frustum. The frustum can be obtained by splitting a cone through the horizontal plane.