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1800-102-2727This is the complete JEE Main Maths Formula Sheet and Class 12 Formula Sheet for Vector Algebra — Chapter 12 from the Aakash Rapid Revision & Formula Bank. This chapter covers the complete Vector Algebra framework tested in JEE Main: types of vectors (null, unit, equal, collinear, coplanar, position vectors); addition and subtraction laws (triangle law, parallelogram law, polygon law); resultant magnitude and direction formulas; section formula (internal and external division in vectors); resolution and linear combination; linearly dependent and independent vectors — all 7 conditions; scalar (dot) product — definition, all 12 properties, component formula, projection, angle between vectors, work done; vector (cross) product — definition, all 11 properties, determinant form, area of parallelogram, area of triangle, torque; scalar triple product — determinant form, all properties, volume of parallelopiped, coplanarity condition; vector triple product — formula a×(b×c)=(a·c)b–(a·b)c; and applications of vectors to geometry — vector equations of lines, planes, perpendicular distance from point to line and plane, shortest distance between skew lines, and angle bisectors of lines. Vector Algebra contributes 3–5 questions in JEE Main every session. Download the Free PDF for all Vector Algebra formulas in one JEE Main exam-ready reference.
Scroll to explore all Vector Algebra formulas — JEE Main Maths & Class 12 Formula Sheet
Vector Algebra is the mathematical language of direction. Unlike scalars — which are completely specified by a magnitude — vectors carry both magnitude and direction, making them the natural tool for describing displacement, velocity, force, angular momentum, and area. In JEE Main maths, Vector Algebra is a direct bridge between algebra and 3D geometry: the dot product encodes angles and projections; the cross product encodes area and the perpendicular direction; the scalar triple product encodes volume and coplanarity.
For JEE Main maths, Vector Algebra contributes 3–5 questions per session covering scalar and vector products, area of parallelogram/triangle, angle between vectors, scalar triple product (volume/coplanarity), and vector equations of lines and planes. The formulas are compact and the method is systematic: identify what product type is needed (dot/cross/scalar triple), apply the determinant or component formula, and compute. The geometric applications (shortest distance between skew lines, perpendicular distance from point to line/plane) appear as direct 4-mark JEE Main questions.
Download the Free PDF for Vector Algebra to access all types of vectors, all product formulas, all geometric application results, and all linearly dependent/independent vector conditions in one structured JEE Main maths revision reference.
Scalars and Vectors (from PDF — Vector Algebra): A scalar quantity has only magnitude, no direction (mass, speed, volume, density). A vector quantity has both magnitude and direction (velocity, force, displacement, acceleration). Vectors are denoted by bold letters or with arrows; magnitude of vector a is written |a| or a.
11 Types of Vectors (from PDF — Vector Algebra JEE Main):
(1) Null (Zero) vector: Magnitude zero, direction indeterminate; denoted 0. Adding/subtracting 0 leaves any vector unchanged.
(2) Unit vector: Magnitude = 1; â = a/|a|. Used to specify direction. î, ĵ, k̂ are standard unit vectors along positive x, y, z axes.
(3) Equal vectors: a = b iff |a|=|b| AND direction same. Must satisfy both conditions.
(4) Like/Unlike vectors: Like vectors: same direction. Unlike vectors: opposite direction.
(5) Negative vector: –a has same magnitude as a but opposite direction.
(6) Collinear (parallel) vectors: Vectors whose lines of action are parallel to a fixed line. a and b are collinear iff a = λb for some scalar λ.
(7) Coplanar vectors: Vectors lying in the same plane. At least 3 coplanar non-equal vectors required to sum to zero; at least 4 non-coplanar vectors for the same.
(8) Free vectors: Not restricted to a fixed point — can be displaced parallel to themselves.
(9) Localized vectors: Restricted to a fixed point (e.g., position vectors).
(10) Co-initial vectors: Share the same initial point.
(11) Position vectors: For a fixed origin O, the position vector of P is OP = r. AB = (position vector of B) – (position vector of A) = OB – OA = b – a.
Angle between two vectors (from PDF — Vector Algebra): The angle θ between vectors a and b is the angle AOB (0 ≤ θ ≤ π) when both are drawn from the same point O. If θ = π/2 → vectors are orthogonal (perpendicular). If θ = 0 or π → vectors are parallel (or antiparallel). Download the Free PDF for Vector Algebra for all type definitions and examples for JEE Main.
Triangle Law of Vector Addition (from PDF — Vector Algebra): If OA = a and AB = b, then OB = a + b. Three vectors are in equilibrium if they form a closed triangle in magnitude and direction (taken in order). The converse holds: vectors forming a closed polygon sum to zero (polygon law).
Parallelogram Law of Vector Addition (from PDF — Vector Algebra JEE Main): If two vectors P and Q are represented by two adjacent sides OA and OB of a parallelogram OACB, the resultant R = P + Q is represented by the diagonal OC:
Magnitude: R = √(P² + Q² + 2PQ cosθ) where θ is the angle between P and Q.
Direction: tan φ = Q sinθ / (P + Q cosθ) where φ is the angle R makes with P.
Special cases: θ=0° → R=P+Q (maximum resultant); θ=180° → R=|P–Q| (minimum); θ=90° → R=√(P²+Q²), tanφ=Q/P.
Properties of Vector Addition (from PDF — Vector Algebra):
(1) Commutative: a + b = b + a
(2) Associative: (a + b) + c = a + (b + c)
(3) Additive identity: a + 0 = 0 + a = a
(4) Additive inverse: a + (–a) = 0
Vector Subtraction (from PDF — Vector Algebra): a – b = a + (–b). Not commutative: a–b ≠ b–a (opposite direction). |a+b| ≤ |a|+|b| (triangle inequality). |a–b| ≥ ||a|–|b|| (reverse triangle inequality). If |a+b|=|a–b| → a and b are perpendicular (a·b=0).
Section Formula in Vector Algebra (from PDF — JEE Main): Let O be the origin with OA=a and OB=b. Point P dividing AB in ratio m:n:
Internal division: OP = (m·b + n·a)/(m+n) [take m times B's vector + n times A's vector, divide by m+n]
External division: OP = (m·b – n·a)/(m–n) [m≠n]
Midpoint (m=n=1): OP = (a+b)/2
Centroid of triangle with vertices a, b, c: G = (a+b+c)/3
Note from PDF: if P divides AB internally in ratio m:n, then AP:PB = m:n → OP = (m·OB + n·OA)/(m+n). Careful with the order: m multiplies the TERMINAL point B (the latter point), n multiplies the INITIAL point A. Download the Free PDF for Vector Algebra for section formula and centroid examples for JEE Main.
Linear Combination (from PDF — Vector Algebra): Any vector r in the plane of two non-collinear vectors a and b can be uniquely written as r = xa + yb (unique x, y scalars). For three non-coplanar vectors a, b, c: any vector r = xa + yb + zc (unique x, y, z). This is the fundamental basis representation in 3D Vector Algebra.
Linearly Dependent Vectors (from PDF — Vector Algebra JEE Main): Vectors a₁, a₂, …, aₙ are linearly dependent if there exist scalars x₁, x₂, …, xₙ (not all zero) such that x₁a₁ + x₂a₂ + … + xₙaₙ = 0. Linearly independent if x₁a₁+…+xₙaₙ=0 implies x₁=x₂=…=xₙ=0.
All 7 Key Results on Linear Dependence (from PDF — Vector Algebra JEE Main):
(1) Three non-coplanar vectors a, b, c are linearly independent.
(2) If a=a₁î+a₂ĵ+a₃k̂, b=b₁î+b₂ĵ+b₃k̂, c=c₁î+c₂ĵ+c₃k̂ are linearly dependent, then the determinant det[aᵢ bᵢ cᵢ] = 0.
(3) Three non-zero vectors α₁a+β₁b+γ₁c, α₂a+β₂b+γ₂c, α₃a+β₃b+γ₃c (where a,b,c are non-coplanar) are coplanar iff det[αᵢ βᵢ γᵢ] = 0.
(4) Two non-zero, non-collinear vectors are linearly independent.
(5) Two collinear vectors, or any three coplanar vectors, or any four vectors in 3D are linearly dependent.
(6) Three points with position vectors a, b, c are collinear iff there exist scalars x, y, z (not all zero) with xa+yb+zc=0 and x+y+z=0.
(7) Four points with position vectors a, b, c, d are coplanar iff there exist scalars x, y, z, w (not all zero) with xa+yb+zc+wd=0 and x+y+z+w=0.
Scalar multiple of a vector (from PDF — Vector Algebra): m·a has magnitude |m|·|a| and same direction if m>0, opposite if m<0. Properties: (m+n)a = ma+na; m(a+b) = ma+mb; m(na) = (mn)a. Download the Free PDF for Vector Algebra for all linear dependence worked examples for JEE Main.
Definition of Scalar (Dot) Product (from PDF — Vector Algebra): The scalar product of vectors a and b, denoted a·b, is defined as:
a·b = |a||b| cosθ where θ is the angle between a and b (0 ≤ θ ≤ π). The result is a scalar.
All 12 Properties of Dot Product (from PDF — Vector Algebra JEE Main):
(1) Commutative: a·b = b·a
(2) Distributive: a·(b+c) = a·b + a·c
(3) Scalar multiple: (ma)·b = m(a·b) = a·(mb)
(4) θ=0 → a·b = |a||b| (like vectors, maximum dot product)
(5) θ=π → a·b = –|a||b| (unlike vectors)
(6) Unit vectors: â·b̂ = cosθ
(7) Self dot product: a·a = |a|² → |a| = √(a·a)
(8) Perpendicularity: a·b = 0 (with a≠0, b≠0) iff a ⊥ b (θ=π/2)
(9) Standard basis vectors: î·î = ĵ·ĵ = k̂·k̂ = 1; î·ĵ = ĵ·k̂ = k̂·î = 0
(10) Component formula: if a=a₁î+a₂ĵ+a₃k̂ and b=b₁î+b₂ĵ+b₃k̂, then:
a·b = a₁b₁ + a₂b₂ + a₃b₃
And: cosθ = (a₁b₁+a₂b₂+a₃b₃) / (√(a₁²+a₂²+a₃²) · √(b₁²+b₂²+b₃²))
(11) Projection of a on b: Component of a in direction of b = a·b̂ = a·b/|b|
Vector projection of a along b: (a·b/|b|²)·b
Component of a perpendicular to b: a – (a·b/|b|²)·b
(12) Work done: W = F·d = |F||d|cosθ where d = AB = displacement vector
Key dot product identities in Vector Algebra (from PDF — JEE Main):
|a+b|² = |a|²+2a·b+|b|²
|a–b|² = |a|²–2a·b+|b|²
(a+b)·(a–b) = |a|²–|b|²
|a+b|²+|a–b|² = 2(|a|²+|b|²) [parallelogram law for magnitudes]
|a+b| = |a–b| iff a·b=0 (diagonals of a parallelogram are equal iff it's a rectangle). Download the Free PDF for Vector Algebra for all dot product examples for JEE Main.
Definition of Vector (Cross) Product (from PDF — Vector Algebra): The vector product of a and b is defined as:
a×b = |a||b| sinθ n̂ where θ (0≤θ≤π) is the angle between a and b, and n̂ is the unit vector perpendicular to both a and b such that a, b, n̂ form a right-handed triad (right-hand screw system). The result is a vector.
All 11 Properties of Cross Product (from PDF — Vector Algebra JEE Main):
(1) Anti-commutative: a×b ≠ b×a. In fact a×b = –(b×a)
(2) Scalar multiple: (ma)×b = m(a×b) = a×(mb)
(3) Distributive: a×(b+c) = a×b + a×c
(4) Parallel vectors: a||b → a×b = 0 (θ=0 or π → sinθ=0). In particular, a×a = 0 for any vector a.
(5) Perpendicular vectors: |a×b| = |a||b| (sinθ=1 when θ=π/2).
(6) Standard basis results: î×î = ĵ×ĵ = k̂×k̂ = 0; and from the cyclic system:
î×ĵ = k̂; ĵ×k̂ = î; k̂×î = ĵ (cyclic: i→j→k→i is positive)
ĵ×î = –k̂; k̂×ĵ = –î; î×k̂ = –ĵ (reverse cyclic is negative)
(7) Unit vector perpendicular to a and b: n̂ = (a×b)/|a×b|
(8) sin θ from cross product: sinθ = |a×b|/(|a||b|)
(9) Determinant formula (from PDF — Vector Algebra):
If a=a₁î+a₂ĵ+a₃k̂ and b=b₁î+b₂ĵ+b₃k̂, then:
a×b = det[î ĵ k̂; a₁ a₂ a₃; b₁ b₂ b₃] = î(a₂b₃–a₃b₂) – ĵ(a₁b₃–a₃b₁) + k̂(a₁b₂–a₂b₁)
(10) Geometric areas (from PDF — Vector Algebra):
If a and b are adjacent sides of a parallelogram: Area = |a×b|
If a and b are diagonals of a parallelogram: Area = (1/2)|a×b|
Area of triangle with sides a and b: Area = (1/2)|a×b|
Area of triangle with vertices P(p), Q(q), R(r): Area = (1/2)|PQ×PR| = (1/2)|(q–p)×(r–p)|
(11) Torque (Moment of Force): M = r×F where r = position vector from point of rotation, F = force vector. |M| = |r||F|sinθ.
Lagrange's identity (from PDF — Vector Algebra JEE Main): |a×b|² = |a|²|b|² – (a·b)² (connects dot and cross product). Equivalently: (a·b)² + |a×b|² = |a|²|b|². Download the Free PDF for Vector Algebra for all cross product and area examples for JEE Main.
Definition of Scalar Triple Product (from PDF — Vector Algebra): For three vectors a, b, c: the scalar triple product [abc] = a·(b×c). This is also written as (a×b)·c. The result is a scalar.
Determinant Formula for STP (from PDF — Vector Algebra JEE Main): If a=a₁î+a₂ĵ+a₃k̂, b=b₁î+b₂ĵ+b₃k̂, c=c₁î+c₂ĵ+c₃k̂, then:
[abc] = a·(b×c) = det[a₁ a₂ a₃; b₁ b₂ b₃; c₁ c₂ c₃]
All properties of Scalar Triple Product (from PDF — Vector Algebra JEE Main):
(1) Volume of parallelopiped: If a, b, c are three adjacent edges of a parallelopiped, Volume = |[abc]|
(2) Cyclic property: [abc] = [bca] = [cab] (cyclic permutations preserve value). Anti-cyclic reversal changes sign: [bac] = –[abc].
Also: a·(b×c) = b·(c×a) = c·(a×b) (dot and cross can be interchanged in cyclic order).
(3) Scalar multiple: [m·a, b, c] = m[abc]; [a, m·b, c] = m[abc]; [a, b, m·c] = m[abc]
(4) Coplanarity condition: Three non-zero, non-collinear vectors a, b, c are coplanar iff [abc] = 0.
Equivalently, the three vectors are coplanar iff the determinant of their components = 0.
(5) If any two vectors in the STP are equal or parallel, [abc] = 0. In particular [aac] = 0, [aba] = 0, etc.
Important STP results (from PDF — Vector Algebra JEE Main):
[î ĵ k̂] = 1 (STP of standard basis = 1, using determinant with 3×3 identity matrix)
[abc]² = det[a·a a·b a·c; b·a b·b b·c; c·a c·b c·c] (Gram's determinant)
Volume of tetrahedron with one vertex at O and adjacent edges a, b, c: V = (1/6)|[abc]|
Volume of tetrahedron with vertices P, Q, R, S: V = (1/6)|[PQ×PR·PS]| = (1/6)|[(q–p) (r–p) (s–p)]|
For tetrahedron OABC: V = (1/6)|[a b c]| where a=OA, b=OB, c=OC.
Four points A, B, C, D (with position vectors a,b,c,d) are coplanar iff [(b–a) (c–a) (d–a)] = 0. Download the Free PDF for Vector Algebra for all STP examples for JEE Main.
Vector Triple Product (from PDF — Vector Algebra): The vector triple product of three vectors a, b, c is defined as a×(b×c). Unlike the scalar triple product (which is a scalar), the vector triple product is a vector lying in the plane of b and c.
BAC-CAB Rule (from PDF — Vector Algebra JEE Main):
a×(b×c) = (a·c)b – (a·b)c
Mnemonic: "BAC minus CAB" — the first vector from the bracket (b) multiplied by the dot product of the outer vector with the last (a·c), minus the last vector from the bracket (c) multiplied by the dot product of the outer with the first (a·b).
(a×b)×c = (a·c)b – (b·c)a
Note from PDF: a×(b×c) ≠ (a×b)×c in general — the vector triple product is NOT associative.
Properties and applications of Vector Triple Product (from PDF — Vector Algebra JEE Main):
a×(b×c) lies in the plane of b and c (always expressible as linear combination of b and c).
(a×b)×c lies in the plane of a and b.
a×(b×c) + b×(c×a) + c×(a×b) = 0 (Jacobi identity).
|a×(b×c)| = |a||b×c|sinθ where θ is the angle between a and b×c.
Lagrange's Identity (from PDF — Vector Algebra):
|a×b|² + (a·b)² = |a|²|b|² = (Lagrange's identity)
Equivalently: |a×b|² = |a|²|b|² – (a·b)²
For unit vectors â and b̂: |â×b̂|² = 1 – cos²θ = sin²θ ✓ (consistent with |â×b̂| = sinθ).
Vector product rules summary (from PDF — Vector Algebra): Dot product: scalar result, commutative, distributive. Cross product: vector result, anti-commutative, distributive, NOT associative. Scalar triple product: scalar result, cyclic. Vector triple product: vector result, NOT associative. BAC-CAB: a×(b×c) = (a·c)b–(a·b)c. Download the Free PDF for Vector Algebra for all triple product examples and JEE Main applications.
Vector Equation of a Straight Line (from PDF — Vector Algebra):
Case I: Line through point with position vector a and parallel to vector b:
r = a + tb (t is scalar parameter, varies over ℝ)
Case II: Line through two points with position vectors a and b:
r = a + t(b–a) equivalently r = (1–t)a + tb
Vector Equation of a Plane (from PDF — Vector Algebra):
Case I: Plane through point a, parallel to vectors b and c:
r = a + sb + tc (s, t are scalar parameters)
Or equivalently: [r – a, b, c] = 0 → [(r–a) b c] = 0
Case II: Plane through three points a, b, c:
r = a + s(b–a) + t(c–a) = (1–s–t)a + sb + tc [s+t≤1 for interior]
Or: [(r–a), (b–a), (c–a)] = 0
Case III: Plane through point a, perpendicular to vector n:
(r – a)·n = 0 equivalently r·n = a·n [normal form; n is normal to plane]
Cartesian equivalent: ax+by+cz=d where n=aî+bĵ+ck̂ and a·n=d.
Perpendicular distance of a point from a line (from PDF — Vector Algebra JEE Main):
Line passes through a and is parallel to b. Perpendicular distance of point r from this line:
d = |(r–a)×b| / |b| [magnitude of cross product divided by |b|]
Alternatively: d = √(|r–a|² – [(r–a)·b/|b|]²) [Pythagoras: subtract the projected component]
Perpendicular distance of a point from a plane (from PDF — Vector Algebra JEE Main):
Case I: Plane through a, parallel to b and c. Distance of point r from plane:
d = |[(r–a) b c]| / |b×c| = |(r–a)·(b×c)| / |b×c|
Case II: Plane through points a, b, c. Distance of point r from plane:
d = |[(r–a) (b–a) (c–a)]| / |(b–a)×(c–a)|
Case III: Plane r·n = d. Distance of origin from plane: |d|/|n|. Distance of point p from plane: |p·n – d|/|n|.
Shortest distance between two non-intersecting (skew) lines (from PDF — Vector Algebra JEE Main):
Let two skew lines pass through a and b and are parallel to c and d respectively. If PQ is the shortest distance, n = c×d (perpendicular to both lines).
SD = |[(b–a) c d]| / |c×d| = |(b–a)·(c×d)| / |c×d|
The shortest distance is along n (perpendicular to both lines). SD = 0 iff the lines are coplanar (intersecting or parallel).
Angle bisectors of two lines in Vector Algebra (from PDF): Two lines meet at A (position vector a), parallel to b and c respectively. Equation of internal bisector: r = a + t(b̂ + ĉ) = a + t(b/|b| + c/|c|). External bisector: r = a + t(b̂ – ĉ) = a + t(b/|b| – c/|c|). Download the Free PDF for Vector Algebra for all geometry applications and JEE Main examples.
All 11 types of vectors (null/unit/equal/like/unlike/negative/collinear/coplanar/free/localized/co-initial/position vector), AB=OB–OA relation, angle between vectors, triangle and polygon laws of addition, parallelogram law (R=√(P²+Q²+2PQcosθ), tanφ=Qsinθ/(P+Qcosθ)), special cases (θ=0/180°/90°), all 4 addition properties, vector subtraction, |a+b|=|a–b|→perpendicular, section formula (internal (mb+na)/(m+n), external, midpoint (a+b)/2, centroid (a+b+c)/3), resolution (orthogonal and non-orthogonal), linear combination, all 7 linear dependence/independence conditions (with collinearity and coplanarity of points), scalar multiple properties, dot product definition (a·b=|a||b|cosθ), all 12 dot product properties (commutative/distributive/scalar multiple/self-dot/perpendicular condition/î·ĵ=0 etc.), component formula (a₁b₁+a₂b₂+a₃b₃), cosθ formula, projection of a on b (a·b/|b|), component perpendicular to b, work done (W=F·d), dot product identities (|a+b|², parallelogram law), cross product definition (a×b=|a||b|sinθ n̂), all 11 cross product properties (anti-commutative/distributive/parallel→0/î×ĵ=k̂ cyclic system), determinant formula for a×b, unit perpendicular (a×b)/|a×b|, sinθ formula, area of parallelogram |a×b| and (1/2)|a×b| for diagonals/triangle, torque M=r×F, Lagrange's identity, scalar triple product [abc]=a·(b×c)=det, all STP properties (volume parallelopiped/cyclic/coplanarity condition/equal→0), volume tetrahedron (1/6)|[abc]|, vector triple product a×(b×c)=(a·c)b–(a·b)c (BAC-CAB), Jacobi identity, vector equations of line (2 forms)/plane (3 cases), perpendicular distance formulas (point to line, point to plane — 3 cases), SD between skew lines, and angle bisector equation are compiled in the Aakash Rapid Revision & Formula Bank PDF — structured for JEE Main maths, Class 12 CBSE, and all engineering entrance exams.
The dot product answers three different question types with one formula. a·b = |a||b|cosθ gives angle between vectors when written as cosθ = a·b/(|a||b|). It gives projection of a on b when divided by |b|. It gives work done when F and d are the vectors. One formula, three JEE Main applications — all pure substitution in the component form a₁b₁+a₂b₂+a₃b₃.
The cross product answers area and perpendicularity questions directly. Area of triangle with two sides a and b = (1/2)|a×b|. Area of parallelogram = |a×b|. Unit vector perpendicular to a and b = (a×b)/|a×b|. The determinant form of a×b is the computation formula. Recognition: if the question asks for area or perpendicular direction → cross product. If it asks for angle or projection → dot product.
The scalar triple product [abc] is one formula for two completely different concepts. |[abc]| = volume of the parallelopiped with edges a, b, c. [abc] = 0 = coplanarity of a, b, c (or equivalently, the four points are coplanar). One determinant evaluation answers both the volume problem and the coplanarity problem in Vector Algebra.
Shortest distance between skew lines is a direct STP application. SD = |[b–a, c, d]|/|c×d| — the numerator is a scalar triple product (determinant), denominator is a cross product magnitude. Both are standard Vector Algebra computations. This formula appears in JEE Main as a 4-mark question that takes under 3 minutes for a student who knows the formula. Download the Free PDF for Vector Algebra to have all these formulas ready.
After working through Vector Algebra using this formula sheet, a student should confidently accomplish the following for JEE Main maths. Types and basics: define each of the 11 types of vectors; write AB = b–a for position vectors; compute resultant magnitude and direction using the parallelogram law; apply section formula (internal/external) and midpoint formula; state centroid of triangle formula. Linear dependence: test linear dependence using the determinant condition; identify when three points are collinear or four points are coplanar using the scalar conditions.
Dot product: compute a·b = a₁b₁+a₂b₂+a₃b₃; find angle between vectors using cosθ = a·b/(|a||b|); test perpendicularity (a·b=0); find projection of a on b; apply work done W=F·d; use |a+b|² and |a–b|² expansions.
Cross product: compute a×b using the 3×3 determinant; apply the cyclic î×ĵ=k̂ rules; find the unit vector perpendicular to two given vectors; compute area of triangle and parallelogram; compute torque.
Scalar triple product: evaluate [abc] as a 3×3 determinant; use volume=|[abc]| and tetrahedron volume=(1/6)|[abc]|; test coplanarity [abc]=0; apply cyclic property.
Vector triple product: apply BAC–CAB: a×(b×c)=(a·c)b–(a·b)c and (a×b)×c=(a·c)b–(b·c)a. Geometry: write vector equation of line and plane; find perpendicular distance from point to line/plane; find shortest distance between skew lines using SD=|[b–a,c,d]|/|c×d|. Download the Free PDF for Vector Algebra to test all outcomes before your JEE Main exam.
The Aakash Rapid Revision & Formula Bank PDF for Vector Algebra covers all definitions, addition laws, section formulas, all three product types (dot, cross, scalar triple), vector triple product, and all geometric applications in one structured JEE Main maths reference. Every formula in this page comes directly from this PDF.
Vector Algebra gives three products — dot, cross, and scalar triple — that together solve the entire range of JEE Main vector geometry problems. The dot product measures alignment (angle, projection, perpendicularity). The cross product measures the perpendicular direction and area. The scalar triple product measures volume and coplanarity. Together, they replace coordinate geometry calculations with elegant vector formulas that are often faster, more general, and geometrically more intuitive.
For JEE Main revision, approach Vector Algebra in four passes. First: types of vectors, position vectors, section formula, and linear combination — these are direct recall questions worth 1 mark each. Second: dot product component formula, perpendicularity test, projection formula, and cosθ formula — these appear in angle and perpendicularity questions. Third: cross product determinant formula, î×ĵ=k̂ cyclic rules, area formulas — these appear in area and unit-perpendicular questions. Fourth: scalar triple product determinant, coplanarity condition, volume formula, shortest distance between skew lines — these are the 4-mark geometry questions. Use this page and the Free PDF Download for Vector Algebra as your complete JEE Main revision foundation.
In Vector Algebra, the dot (scalar) product of vectors a and b is a·b = |a||b|cosθ where θ is the angle between them. In component form: if a=a₁î+a₂ĵ+a₃k̂ and b=b₁î+b₂ĵ+b₃k̂, then a·b = a₁b₁+a₂b₂+a₃b₃. JEE Main applications: (1) Angle: cosθ = a·b/(|a||b|) = (a₁b₁+a₂b₂+a₃b₃)/(√(a₁²+a₂²+a₃²)·√(b₁²+b₂²+b₃²)). (2) Perpendicularity: a⊥b iff a·b=0. (3) Projection of a on b: a·b̂ = a·b/|b|. (4) Component along b: (a·b/|b|²)b; perpendicular to b: a–(a·b/|b|²)b. (5) Self-dot: a·a=|a|². (6) Work done: W=F·d. Key basis results: î·î=ĵ·ĵ=k̂·k̂=1; î·ĵ=ĵ·k̂=k̂·î=0. Key identities: |a+b|²=|a|²+2a·b+|b|²; |a+b|=|a–b| iff a·b=0; |a+b|≤|a|+|b| (triangle inequality). These Vector Algebra dot product formulas cover every angle, projection, and perpendicularity JEE Main question type.
In Vector Algebra, the cross product a×b = |a||b|sinθ n̂ where n̂ is perpendicular to both a and b by the right-hand rule. Determinant formula: a×b = det[î ĵ k̂; a₁ a₂ a₃; b₁ b₂ b₃] = î(a₂b₃–a₃b₂) – ĵ(a₁b₃–a₃b₁) + k̂(a₁b₂–a₂b₁). Basis cross products from the cyclic rule (î→ĵ→k̂→î is positive): î×ĵ=k̂; ĵ×k̂=î; k̂×î=ĵ. Reversals are negative: ĵ×î=–k̂; k̂×ĵ=–î; î×k̂=–ĵ. Self-cross: î×î=ĵ×ĵ=k̂×k̂=0. Key properties: anti-commutative (a×b=–b×a); parallel iff a×b=0; unit perpendicular n̂=(a×b)/|a×b|; sinθ=|a×b|/(|a||b|). Area applications: adjacent sides a,b → area parallelogram=|a×b|; diagonals a,b → area=(1/2)|a×b|; triangle with sides a,b → area=(1/2)|a×b|. Torque: M=r×F. Lagrange's: |a×b|²+(a·b)²=|a|²|b|². These Vector Algebra cross product results cover area and perpendicular direction JEE Main questions.
In Vector Algebra, the scalar triple product of a, b, c is [abc] = a·(b×c) = det[a₁a₂a₃; b₁b₂b₃; c₁c₂c₃]. Key properties: (1) Cyclic: [abc]=[bca]=[cab]. Anti-cyclic reversal: [bac]=–[abc]. Also: a·(b×c)=b·(c×a)=c·(a×b) (dot and cross can be exchanged in cyclic order). (2) Volume: |[abc]| = volume of parallelopiped with edges a, b, c. Volume of tetrahedron = (1/6)|[abc]|. (3) Coplanar iff [abc]=0. Equivalently: the determinant of component matrix = 0. (4) [mabc]=m[abc]. (5) If any two vectors are equal or parallel: [abc]=0. (6) [îĵk̂]=1. Four points A,B,C,D coplanar: [(b–a)(c–a)(d–a)]=0. This is the key Vector Algebra formula: one determinant simultaneously gives the volume (|[abc]|) and the coplanarity test ([abc]=0). Every JEE Main STP question reduces to evaluating this 3×3 determinant.
In Vector Algebra, the vector triple product a×(b×c) is evaluated using the BAC-CAB rule: a×(b×c) = (a·c)b – (a·b)c. Memory: "Back-Cab" — the result is a linear combination of b and c where b gets the dot product of a with c, and c gets the negative of the dot product of a with b. For (a×b)×c: (a×b)×c = (a·c)b – (b·c)a. Note: (a×b)×c ≠ a×(b×c) — the vector triple product is NOT associative. Key fact: a×(b×c) lies in the plane of b and c (expressible as linear combination αb+βc). Similarly (a×b)×c lies in the plane of a and b. Jacobi identity: a×(b×c)+b×(c×a)+c×(a×b)=0. Applications in JEE Main Vector Algebra: proving vector identities, simplifying expressions involving three vectors. Example: if a, b, c are mutually perpendicular unit vectors, then a×(b×c) = (a·c)b–(a·b)c = 0·b–0·c = 0 (since a⊥b and a⊥c, their dot products = 0).
In Vector Algebra, the vector equation of a line through point a parallel to direction vector b is r = a + tb (t∈ℝ). Line through two points a and b: r = a + t(b–a) = (1–t)a + tb. To find if point r₀ lies on line r=a+tb: check if (r₀–a) = tb for some scalar t, i.e., (r₀–a) is parallel to b, i.e., (r₀–a)×b=0. Vector equation of a plane: (1) Through point a parallel to vectors b and c: r = a+sb+tc; equivalent condition: [(r–a) b c]=0. (2) Through three points a, b, c: r=a+s(b–a)+t(c–a); condition: [(r–a)(b–a)(c–a)]=0. (3) Through point a perpendicular to n: (r–a)·n=0 → r·n=a·n=d (scalar form). Cartesian: n₁x+n₂y+n₃z=d. Angle between two planes with normals n₁ and n₂: cosθ=|n₁·n₂|/(|n₁||n₂|). Angle between line direction b and plane normal n: sinθ=|b·n|/(|b||n|) (complement of angle with plane). These Vector Algebra line/plane equations are tested in JEE Main and are the bridge to 3D Geometry.
In Vector Algebra, two skew lines (non-intersecting, non-parallel) with: Line 1 passing through a and parallel to c; Line 2 passing through b and parallel to d. The shortest distance between them is: SD = |[(b–a) c d]| / |c×d| = |(b–a)·(c×d)| / |c×d|. This formula is derived as follows: the common perpendicular to both lines is along n = c×d. The shortest distance equals the projection of the vector (b–a) connecting any two points on the two lines onto n: SD = |(b–a)·n̂| = |(b–a)·(c×d)|/|c×d|. The numerator |(b–a)·(c×d)| = |[(b–a) c d]| is a scalar triple product — evaluable as a 3×3 determinant. SD=0 iff the lines are coplanar (either intersecting or parallel). Direction of common perpendicular: c×d. Key: express the numerator as [b–a, c, d] and evaluate the determinant, divide by |c×d|. This Vector Algebra shortest distance formula appears in JEE Main and JEE Advanced as a direct 4-mark question.
In Vector Algebra, if A has position vector a and B has position vector b, the point P dividing AB internally in the ratio m:n has position vector: OP = (m·b + n·a)/(m+n). [m times the terminal point B's vector plus n times the initial point A's vector, divided by m+n.] External division in m:n (m≠n): OP = (m·b – n·a)/(m–n). Midpoint (m=n=1): OP = (a+b)/2. Centroid of triangle (a,b,c): G = (a+b+c)/3. Three things to remember in Vector Algebra: (1) Internal division uses + in denominator; (2) The "m" multiplies the point being divided TOWARDS (terminal point B, the one closer to m); (3) External division has – in denominator. Applications in JEE Main Vector Algebra: finding the point dividing a segment, centroid, and position of a point on a line. If line passes through a and b, the point 1/3 of the way from A to B: t=1/3 → position = a+(1/3)(b–a)=(2a+b)/3. The section formula is also used to verify collinearity: A, B, C are collinear iff C divides AB in some ratio, i.e., c=(mb+na)/(m+n) for some m,n.
In Vector Algebra, three vectors a, b, c are coplanar iff [abc] = a·(b×c) = 0, i.e., the scalar triple product equals zero, i.e., the 3×3 determinant of their components is zero. This is equivalent to: one of the three vectors is a linear combination of the other two. For four points with position vectors p, q, r, s: they are coplanar iff the vectors (q–p), (r–p), (s–p) are coplanar, i.e., [(q–p)(r–p)(s–p)] = 0. Equivalently: the parallelepiped formed by (q–p), (r–p), (s–p) has zero volume (they all lie in one plane). In JEE Main Vector Algebra, coplanarity questions either give three vectors and ask to find a parameter (set [abc]=0, solve) or give four points and ask to verify/find conditions ([b–a, c–a, d–a]=0). Linear dependence connection: three vectors a,b,c are linearly dependent iff they are coplanar iff [abc]=0. Any four vectors in 3D are always linearly dependent (and therefore any set of 4 vectors has some coplanar subset). Minimum 3 non-collinear, non-zero vectors can be coplanar; for them to not be, they must span all three dimensions.
In Vector Algebra, area of a triangle: (1) With two sides represented by vectors a and b: Area = (1/2)|a×b|. This follows because the cross product gives the area of the parallelogram formed by a and b, and the triangle is half of that. (2) With vertices at points P, Q, R (position vectors p, q, r): Let PQ = q–p and PR = r–p. Area = (1/2)|PQ×PR| = (1/2)|(q–p)×(r–p)|. (3) Diagonals of parallelogram given as d₁ and d₂: Area of parallelogram = (1/2)|d₁×d₂|. Area of each triangle = (1/4)|d₁×d₂|. Comparison in Vector Algebra: Adjacent sides a,b → parallelogram area |a×b|, triangle area (1/2)|a×b|. Diagonals a,b → parallelogram area (1/2)|a×b|. Example: triangle with vertices A(1,2,3), B(4,5,6), C(7,8,0). AB=3î+3ĵ+3k̂; AC=6î+6ĵ–3k̂. AB×AC = det[î ĵ k̂; 3 3 3; 6 6 –3] = î(3·(–3)–3·6)–ĵ(3·(–3)–3·6)+k̂(3·6–3·6) = î(–9–18)–ĵ(–9–18)+k̂(0) = –27î+27ĵ. |AB×AC|=27√2. Area=27√2/2. These Vector Algebra area formulas appear in JEE Main as direct computation questions.
In Vector Algebra, the Triangle Law of Addition states: if OA=a and AB=b, then OB=a+b. The triangle OAB has sides OA, AB, OB. Three vectors form a closed triangle (their resultant is zero) when taken in order. The Parallelogram Law states: if two vectors P and Q are represented by adjacent sides OA and OB of a parallelogram, the resultant R=P+Q is the diagonal OC. Magnitude: R=√(P²+Q²+2PQcosθ) where θ is angle between P and Q. Direction: tanφ=Qsinθ/(P+Qcosθ) where φ is the angle R makes with P. Special cases in Vector Algebra JEE Main: θ=0° (same direction): R=P+Q (maximum); θ=180° (opposite): R=|P–Q| (minimum); θ=90°: R=√(P²+Q²), tanφ=Q/P. Polygon Law: if any number of vectors form a closed polygon (taken in order), their resultant is 0. Conversely: if n vectors a₁,a₂,…,aₙ satisfy a₁+a₂+…+aₙ=0, they form a closed polygon. These Vector Algebra addition laws are tested in JEE Main directly as "find resultant magnitude/direction" questions.
Vector Algebra – JEE Main Maths Formula Sheet