?

The Principal Value Branch of Sec    (x) Is

-1

By Team Aakash Byju's | 13th November 2022

[0, π] - {      }

(0, π)

(π,      )

(0, π) - {      }

Your options are

A

B

D

C

π

2

π

2

π

4

Arrow

Detailed Explanation

The correct answer is  A. Principal value of  sec     (x) = [0, π] - {      }

-1

π

2

The principal value is the value of the inverse trigonometric function lying in the range of its principal branch.

The smallest value of θ, either positive or negative .

Function

Domain

x

Range

y

sin   x

cos   x

tan   x

cosec   x

sec    x

cot    x

-1

-1

-1

-1

-1

-1

[-1,1]

[-1,1]

R=(-∞,∞)

R-(-1,1)

R-(-1,1)

R

[           ]

π

2

-

,

π

2

[0 , π  ]

(            )

-

π

2

π

2

,

π

2

-

π

2

,

[           ]

,

y ≠ 0

y ≠

[           ]

,

-

π

2

π

2

π

2

,

 (0 ,  )

π

We know that the domain of the function y = sec    (x) is x ≤ -1 or x ≥ 1.

-1

y = sec   x

-1

So, the valid range for sec(y) = x is between 0 and π.

sec     (-1) = π and sec     (1) = 0

Range for sec(y) = x is [0, π]

-1

-1

y = sec   x

-1

y = sec   x

π

2

π

2

cos(      ) = 0

π

2

sec(      ) = 

π

2

cos(      )

π

2

1

=

1

0

sec(      ) = 

π

2

undefined

But, sec(      ) is undefined as cos(      ) = 0

-1

y = sec   x

Therefore, the principal value branch of sec     (x) will be

-1

[0, π] -

{       }

π

2

-1