By Team Aakash Byju's | 16th January 2023
Construct a quadrilateral PQRS where PQ = 4 cm, QR = 6 cm, RS = 5 cm, PS = 5.5 cm and PR = 7 cm.
R
S
4 cm
P
Q
5.5 cm
6 cm
5 cm
7 cm
From the given data, it can be noted that PR is a line that shares lines with both Q and S. Thus, PR is a diagonal of the quadrilateral. Let us draw PR = 7 cm using a ruler.
P
R
Take a compass, keep the radius as 4 cm and draw an arc from P (centre) on top of line PR as shown below.
P
R
Next, set the radius to 6 cm and draw an arc from R (centre) in such a way that it meets the previously drawn arc as shown below.
P
R
Now, keep the radius to 5.5 cm and set P as the centre to draw an arc below the line PR. Similarly, keep the radius to 5 cm and R as a centre to draw an arc meeting the previous arc as shown below.
P
R
Label the point of intersection of arcs above PR as Q and the point of intersection of arcs below PR as S. Now, join PQ, QR, PS and RS as shown below.
P
Q
5.5 cm
R
6 cm
4cm
Thus Quadrilateral PQRS is constructed as shown.
S
5 cm
7 cm