By Team Aakash Byju's | 19th January 2023
When a copper sphere is heated, maximum percentage change will be observed in the:
Q .
A
B
C
D
Area
Radius
Volume
None of the above
Let R be the radius of the sphere. When it is heated, it gets expanded and thus its radius, area and volume will increase. We know that,
R
Area of the sphere = 4π R
Volume of the sphere = π R
4
3
2
3
Let ∆R, ∆ A and ∆V be the change in radius, area and volume respectively. Then,
Change in radius =
∆R
R
=
x(say)
Change in area =
4π (∆R)
( )=
R
=
∆R
R
x
2
2
2
Change in volume =
π (∆R)
3
4
3
4
3
R
3
π
( )=
=
∆R
R
x
3
3
Area= 4πr
2
Volume = πr
4
3
3
4π
2
Since the power of x is the maximum for volume, when a copper sphere is heated, the maximum percentage change will be in volume.