By Team Aakash Byju's | 17th November 2022
Question Continues
If the lengths and radii of the wires are in the ratio of and , then the ratio of the currents passing through the wire will be
4
3
1
4
3
1
2
3
4
3
2
3
Detailed Explanation
3
1
Where, V is the potential difference across the wire
R is the resistance
I =
V
R
R= ρ
l
πr
2
of the wire.
1
2
l =
V
R
1
and
l =
V
R
2
l
1
l
2
=
1
2
R
1
R
2
Parallel resistance
l
1
l
2
=
R
1
R
2
=
ρ
l
2
πr
2
2
ρ
l
1
1
2
πr
=
r
l
2
1
2
l
1
2
r
2
=>
l
1
l
2
=
l
1
l
2
.
r
1
r
2
2
Resistance
l
1
l
2
=
3
4
2
3
2
l
1
l
2
3
4
r
1
r
2
2
3
.
=
3
4
.
4
9
=
l
3
Thus, the ratio of currents passing through the wire is
l
3
=>
.