By Team Aakash Byju's | 11th November 2022

Finding the Frictional Force Required by a Bicycle Rider

?

The mass of the bicycle rider along with the bicycle is 100 kg. He wants to cross over a circular turn of radius 100 m with a speed of 10 ms-1. (Question continues)

The coefficient of friction between the tyres and the road is 0.6. The Frictional force required by the rider to cross the turn is

250 Newton

A

B

C

D

300 Newton

400 Newton

600 Newton

Detailed Explanation

The correct option is  D. 600 Newton.

Arrow

The expression for Centripetal force acting upon a body is written as:

Where,  m is the mass of the body, v is the velocity with which the body moves and r is the radius of the circular path.

F  =

mv

r

2

c

Given, m = 100 kg, v = 10 ms   and r = 100 m.  Using these, we find the centripetal force as:

Fc =

mv

r

=

100 × 10

100

=

100 Newton

2

2

1

-

Therefore, the Frictional Force needed to cross the turn of radius 100 m, and a coefficient of friction 0.6 between the tyres and the road is,

µmg

F  =

f

F  =

f

0.6 × 100 × 10

=

600 Newton