By Team Aakash Byju's | 26th January 2023
Gauss law is applied in the case of a charged ring of radius R on its axis at a distance x from the centre of the ring.
E=
4πε
1
(R +x )
qx
2
2
3
2
At the centre, x = 0 and E = 0.
x=R
O
P
0
It is applied in the case of an infinite line of charge, at a distance, ‘r’.
E=
4πrε
( )
( )
1
2π
r
Where λ is the linear charge density.
E=
2πrε
λ
0
0
In the case of the intensity of the electric field near a plane sheet of charge.
E=
2ε k
σ
where σ = surface charge density.
0
E
E
A
Gaussian surface
In the case of the intensity of the electric field near a plane-charged conductor
E=
k ε
σ
in a medium of dielectric constant K.
If the dielectric medium is air, then E .
air
=
σ
ε
0
0
E
E
A
Gaussian surface
In the case where the field between two parallel plates of a condenser is
E=
ε
σ
where σ is the surface charge density.
0
d
v
A
B
v
v=0
q