{"id":199392,"date":"2022-06-21T08:30:48","date_gmt":"2022-06-21T03:00:48","guid":{"rendered":"https:\/\/www.aakash.ac.in\/blog\/?p=199392"},"modified":"2023-05-02T12:58:54","modified_gmt":"2023-05-02T07:28:54","slug":"neet-chemistry-previous-year-questions-with-solutions","status":"publish","type":"post","link":"https:\/\/www.aakash.ac.in\/blog\/neet-chemistry-previous-year-questions-with-solutions\/","title":{"rendered":"NEET Chemistry Previous Year Questions With Solutions"},"content":{"rendered":"

<\/a>
\nNEET exam comprises <\/span>Physics<\/span>, <\/span>Chemistry<\/span>, and <\/span>Biology<\/span> sections. Among the three, the overpowered section by its weightage is <\/span>Biology<\/span>. So, most students give preference to it. But, do not forget that without <\/span>Physics<\/span> and Chemistry, you cannot qualify for the NEET 2022.<\/span><\/p>\n

Many of you may be afraid of Chemistry, as it is a complete concept based and contains very few numerical parts. But, if you draw some strategy like linking the concepts of one topic with another, then you will find it a very easy-going section in the <\/span>NEET 2022 exam<\/span><\/a> paper.<\/span><\/p>\n

This article contains the most common and important questions of Chemistry for NEET previous year question papers<\/a>. Have a look.<\/span><\/p>\n

Previous Years\u2019 Important Questions of NEET Chemistry With Solutions<\/b><\/h4>\n

<\/a><\/p>\n

Here are some important questions from the last three previous years\u2019 papers for the NEET exam. Some of them are repeated but in a tricky way.<\/span><\/p>\n

1. Which one of the following ions exhibits d-d transitions?<\/p>\n

    \n
  1. CrO<\/span>4<\/span>-2<\/span><\/li>\n
  2. Cr<\/span>2<\/span>O<\/span>7<\/span>-2<\/span><\/li>\n
  3. MnO<\/span>4<\/span>-2<\/span><\/li>\n
  4. MnO<\/span>4<\/span>–<\/span><\/li>\n<\/ol>\n

    <\/b> The correct option is (c).<\/span><\/p>\n

    In MnO<\/span>4<\/span>-2<\/span>, the oxidation state of Mn is (+6). As a result, it has one unpaired electron in its d-orbit. Hence, it will exhibit paramagnetic behaviour. And also shows the d-d transition.<\/span><\/p>\n

    2. Hydrocarbon (A) reacts with bromine. It forms an alkyl bromide on substitution, converted to a gaseous hydrocarbon by the Wurtz reaction. This hydrocarbon contains less than four carbon atoms. (A) is<\/span><\/p>\n

      \n
    1. CH<\/span>4<\/span><\/li>\n
    2. CH <\/span> CH<\/span><\/li>\n
    3. CH<\/span>3<\/span> – CH<\/span>3<\/span><\/li>\n
    4. CH<\/span>2<\/span> = CH<\/span>2<\/span><\/li>\n<\/ol>\n

      <\/b>The correct option is (a).<\/span><\/p>\n

      Methane (CH<\/span>4<\/span>) undergoes a substitution reaction to form ethyl bromide, which further undergoes a Wurtz reaction to form ethane.<\/span><\/p>\n

      3. When the initial concentration of the reactant is doubled, the half period of the zero-order reaction is<\/span><\/p>\n

        \n
      1. tripled<\/span><\/li>\n
      2. halved<\/span><\/li>\n
      3. doubled<\/span><\/li>\n
      4. remains the same<\/span><\/li>\n<\/ol>\n

        <\/b> The correct option is (c).<\/span><\/p>\n

        The half-life period of the zero-order reaction is directly proportional to the concentration of the reactant. Therefore, if the concentration of the reactant is doubled, the half-life period will also get doubled.<\/span><\/p>\n

        4. Which one of the following conditions will follow the maximum formation of the product in the reaction,<\/span><\/p>\n

        A<\/span>2<\/span> (g) + B<\/span>2<\/span> (g) \u21cb X<\/span>2<\/span> (g)\u00a0 <\/span>f<\/span>H<\/span> = -X kJ?<\/span><\/p>\n

          \n
        1. High temperature and low pressure<\/span><\/li>\n
        2. Low pressure and high temperature<\/span><\/li>\n
        3. High temperature and high pressure<\/span><\/li>\n
        4. Low temperature and low-pressure<\/span><\/li>\n<\/ol>\n

          <\/b> The correct option is (b).<\/span><\/p>\n

          Exothermic reactions are best carried out at low temperatures and high pressures so that the equilibrium is shifted in the forward direction.<\/span><\/p>\n

          Also See: NEET Chemistry Important Preparation Tips<\/a><\/p>\n

          5. The difference between Amylose and Amylopectin is<\/p>\n

            \n
          1. Amylose is made up of <\/span>galactose and glucose.<\/span><\/li>\n
          2. Amylopectin has 1 \u2192 4 <\/span>-linkage and 1 <\/span> 6 <\/span>-linkage<\/span><\/li>\n
          3. Amylopectin has 1 \u2192 4 <\/span>-linkage and 1 <\/span> 6 <\/span>-linkage<\/span><\/li>\n
          4. Amylose has 1 \u2192 4 <\/span>-linkage and 1 <\/span> 6 <\/span>-linkage<\/span><\/li>\n<\/ol>\n

            The correct option is (c).<\/span><\/p>\n

            Amylose is a less branched chain of <\/span> 1 \u2192 4 glycosidic linkages, whereas Amylopectin is heavily branched and contains <\/span> 1 \u2192 4 glycosidic linkages and <\/span> 1 \u2192 4 glycosidic linkages.<\/span><\/p>\n

            6. For the redox reaction,<\/span><\/p>\n

            MnO<\/span>4<\/span>–<\/span> + H<\/span>+<\/span> + C<\/span>2<\/span>O<\/span>4<\/span>2-<\/span> \u2192 Mn<\/span>2+<\/span> + H<\/span>2<\/span>O + CO<\/span>2<\/span><\/p>\n

            the correct coefficient of the reactants for this balanced reaction is:<\/span><\/p>\n\n\n\n\n\n\n\n
            <\/td>\nMnO<\/b>4<\/b>–<\/b><\/td>\nC<\/b>2<\/b>O<\/b>4<\/b>2-<\/b><\/td>\nH<\/b>+<\/b><\/td>\n<\/tr>\n
            (a)<\/span><\/td>\n5<\/span><\/td>\n16<\/span><\/td>\n2<\/span><\/td>\n<\/tr>\n
            (b)<\/span><\/td>\n16<\/span><\/td>\n5<\/span><\/td>\n2<\/span><\/td>\n<\/tr>\n
            (c)<\/span><\/td>\n2<\/span><\/td>\n16<\/span><\/td>\n5<\/span><\/td>\n<\/tr>\n
            (d)<\/span><\/td>\n2<\/span><\/td>\n5<\/span><\/td>\n16<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

            The correct option is (d).<\/span><\/p>\n

            KMnO<\/span>4<\/span> acts as an oxidising agent in an acidic medium, and its n factor is 5, while the n factor of oxalate ion is 2.<\/span><\/p>\n

            7. Identify the compound X in the following reaction<\/span><\/p>\n

            The correct option is (c).<\/p>\n

            Also See: NEET Chemistry Chapterwise Important Questions<\/a><\/p>\n

            8. An element has a bcc (body-centered cubic) structure. It has a cell edge of 288 pm. This element’s atomic radius is:<\/span><\/p>\n

              \n
            1. 3<\/span>4<\/span> x 288 pm<\/span><\/li>\n
            2. 2<\/span>4<\/span> x 288 pm<\/span><\/li>\n
            3. 4<\/span>3<\/span> x 288 pm<\/span><\/li>\n
            4. 4<\/span>2<\/span> x 288 pm<\/span><\/li>\n<\/ol>\n

              <\/b> The correct option is (a).<\/span><\/p>\n

              In a bcc unit cell, atoms lying along with a diagonal body touch each other.<\/span><\/p>\n

              Length of body diagonal = <\/span>3<\/span>a<\/span><\/p>\n

              3<\/span>a = 4r<\/span><\/p>\n

              r = <\/span>3<\/span>4<\/span> a<\/span><\/p>\n

              As a = 288 pm<\/span><\/p>\n

              r = <\/span>3<\/span>4<\/span> x 288 pm<\/span><\/p>\n

              9. Reaction between methyl magnesium chloride and acetone followed by hydrolysis will give:<\/p>\n

                \n
              1. Isopropyl alcohol<\/span><\/li>\n
              2. Secondary butyl alcohol<\/span><\/li>\n
              3. Isobutyl alcohol<\/span><\/li>\n
              4. Tertiary butyl alcohol<\/span><\/li>\n<\/ol>\n

                <\/b> The correct option is (d).<\/span><\/p>\n

                10. The calculated spin only magnetic moment of Cr<\/span>2+<\/span> ion is:<\/span><\/p>\n

                  \n
                1. 4.90 BM<\/span><\/li>\n
                2. 5.92 BM<\/span><\/li>\n
                3. 3.87 BM<\/span><\/li>\n
                4. 2.84 BM<\/span><\/li>\n<\/ol>\n

                  <\/b> The correct option is (a).<\/span><\/p>\n

                  Electronic configuration of Cr = [Ar] 3d<\/span>5<\/span> 4s<\/span>1<\/span><\/p>\n

                  Electronic configuration of Cr<\/span>2+<\/span> = [Ar] 3d<\/span>4<\/span><\/p>\n

                  Number of unpaired electrons = 4<\/span><\/p>\n

                  Spin only magnetic moment, <\/span> = <\/span>n (n+2)<\/span> BM<\/span><\/p>\n

                  As n = 4<\/span><\/p>\n

                  = <\/span>4 (4+2)<\/span> BM<\/span><\/p>\n

                  = 4.90 BM<\/span><\/p>\n

                  Also See: Best Books for NEET 2022 Chemistry<\/a><\/p>\n

                  12. Which of the following is the correct increasing order of the field strength of ligands to form coordination compounds?<\/p>\n

                    \n
                  1. SCN<\/span>–<\/span> < F<\/span>–<\/span> < C<\/span>2<\/span>O<\/span>4<\/span>2-<\/span> < CN<\/span>–<\/span><\/li>\n
                  2. SCN<\/span>–<\/span> < F<\/span>–<\/span> < CN<\/span>–<\/span> < C<\/span>2<\/span>O<\/span>4<\/span>2-<\/span><\/li>\n
                  3. F<\/span>–<\/span> < SCN<\/span>–<\/span> < C<\/span>2<\/span>O<\/span>4<\/span>2-<\/span> < CN<\/span>–<\/span><\/li>\n
                  4. CN<\/span>–<\/span> < C<\/span>2<\/span>O<\/span>4<\/span>2-<\/span> < SCN<\/span>–<\/span> < F<\/span>–<\/span><\/li>\n<\/ol>\n

                    <\/b>The correct option is (a).<\/span><\/p>\n

                    The arrangement of different ligands in increasing order of the field strength, called spectrochemical series, is as follows:<\/span><\/p>\n

                    I<\/span>–<\/span> < SCN<\/span>–<\/span> < Cl<\/span>–<\/span> < S<\/span>2-<\/span> < F<\/span>–<\/span> < OH<\/span>–<\/span> < C<\/span>2<\/span>O<\/span>4<\/span>2-<\/span> < H<\/span>2<\/span>O < NH<\/span>3<\/span> < CN<\/span>–<\/span> < CO<\/span><\/p>\n

                    13. For the reaction 2Cl (g) \u2192 Cl<\/span>2<\/span> (g), the correct optionis:<\/span><\/p>\n

                      \n
                    1. r<\/span>H<\/span> > 0 and <\/span>r<\/span>S<\/span> > 0<\/span><\/li>\n
                    2. r<\/span>H<\/span> > 0 and <\/span>r<\/span>S<\/span> < 0<\/span><\/li>\n
                    3. r<\/span>H<\/span> < 0 and <\/span>r<\/span>S<\/span> > 0<\/span><\/li>\n
                    4. r<\/span>H<\/span> < 0 and <\/span>r<\/span>S<\/span> < 0<\/span><\/li>\n<\/ol>\n

                      <\/b> The correct option is (d).<\/span><\/p>\n

                      2Cl (g) \u2192 Cl<\/span>2<\/span> (g)<\/span><\/p>\n

                      As the process involves bond formation, <\/span>H = -ve and as the number of gaseous particles decreases in the reaction, <\/span>S is also -ve, i.e., <\/span>r<\/span>H<\/span> < 0 and <\/span>r<\/span>S<\/span> < 0.<\/span><\/p>\n

                      14. For any reaction A \u2192 B, the enthalpy of reaction is -4.2 kJ mol-1, and the activation enthalpy is 9.6 kJ mol-1. The correct potential energy outline for the reaction is shown in the option<\/p>\n

                      The correct option is (b).<\/p>\n

                      A \u2192 B is an exothermic reaction. For exothermic reactions, the energy of reactants is always greater than the energy of products.<\/span><\/p>\n

                      15. Which of the following molecules is nonpolar?<\/span><\/p>\n

                        \n
                      1. POCl<\/span>3<\/span><\/li>\n
                      2. SbCl<\/span>5<\/span><\/li>\n
                      3. CH<\/span>2<\/span>O<\/span><\/li>\n
                      4. NO<\/span>2<\/span><\/li>\n<\/ol>\n

                        <\/b> The correct option is (b).<\/span><\/p>\n

                        Here, dipole moment, <\/span> = 0<\/span><\/p>\n

                        16. The compound which shows metamerism is:<\/span><\/p>\n

                          \n
                        1. C<\/span>5<\/span>H<\/span>12<\/span><\/li>\n
                        2. C<\/span>4<\/span>H<\/span>10<\/span>O<\/span><\/li>\n
                        3. C<\/span>3<\/span>H<\/span>8<\/span>O<\/span><\/li>\n
                        4. C<\/span>3<\/span>H<\/span>6<\/span>O<\/span><\/li>\n<\/ol>\n

                          <\/b> The correct option is (b).<\/span><\/p>\n

                          With the formula C<\/span>4<\/span>H<\/span>10<\/span>O the possible ethers are:<\/span><\/p>\n

                            \n
                          1. diethyl ether<\/span><\/li>\n
                          2. methyl n- propyl ether<\/span><\/li>\n
                          3. isopropyl methyl ether<\/span><\/li>\n<\/ol>\n

                            Here, (1) & (3), and (1) & (2) are metamers.<\/span><\/p>\n

                            17. A particular station of All India Radio, New Delhi, broadcasts on 1,368 kHz (kilohertz). The wavelength of electromagnetic radiation released by the transmitter is (speed of light, c = 3 x 108 m\/s)<\/p>\n

                              \n
                            1. 219.2 m<\/span><\/li>\n
                            2. 219.3 m<\/span><\/li>\n
                            3. 21.92 m<\/span><\/li>\n
                            4. 2192 m<\/span><\/li>\n<\/ol>\n

                              <\/b> The correct option is (b).<\/span><\/p>\n

                              = <\/span>c<\/span>v<\/span><\/p>\n

                              = <\/span>3 x 1<\/span>0<\/span>\u2078 m\/s<\/span>1368 x 10\u00b3 S\u207b\u00b9<\/span><\/p>\n

                              = 219.3 m<\/span><\/p>\n

                              18. The intermediate compound \u2018X\u2019 in the following chemical reaction is:<\/p>\n

                              The correct option is (a).<\/p>\n

                              19. The molar conductivity of 0.007M acetic acid is 20 S cm2 mol-1. What is the dissociation constant of acetic acid? Choose the correct option [\u00baH+ = 350 S cm2 mol-1, \u00baCH\u2083COO- = 50 S cm2 mol-1]<\/p>\n

                                \n
                              1. 1.75 x 10<\/span>-4<\/span> molL<\/span>-1<\/span><\/li>\n
                              2. 1.75 x 10<\/span>-5<\/span> molL<\/span>-1<\/span><\/li>\n
                              3. 2.50 x 10<\/span>-4<\/span> molL<\/span>-1<\/span><\/li>\n
                              4. 2.50 x 10<\/span>-5<\/span> molL<\/span>-1<\/span><\/li>\n<\/ol>\n

                                <\/b> The correct option is (b).<\/span><\/p>\n

                                Degree of association (<\/span>) of CH<\/span>3<\/span>COOH = <\/span>C<\/span>O<\/span> = <\/span>20<\/span>350+50<\/span> = <\/span>1<\/span>20<\/span><\/p>\n

                                K<\/span>a<\/span> = <\/span>C<\/span>\u00b2<\/span>1-<\/span><\/p>\n

                                1-<\/span> 1<\/span><\/p>\n

                                K<\/span>a<\/span> = <\/span>C<\/span>\u00b2<\/span><\/p>\n

                                K<\/span>a<\/span> = 1.75 x 10<\/span>-5<\/span><\/p>\n

                                Also See: NEET Chemistry Important Topics<\/a><\/p>\n

                                <\/b>20. The correct option for the value of vapour pressure of a solution at 45\u2103 with octane to benzene in molar ratio 2:3 is [At 45\u2103, the vapour pressure of octane is 420 mm Hg, and that of benzene is 280 mm Hg. Assume the gas is ideal.]<\/span><\/p>\n

                                  \n
                                1. 350 mm Hg<\/span><\/li>\n
                                2. 168 mm Hg<\/span><\/li>\n
                                3. 336 mm Hg<\/span><\/li>\n
                                4. 160 mm Hg<\/span><\/li>\n<\/ol>\n

                                  <\/b> The correct option is (c).<\/span><\/p>\n

                                  Applying Raoult\u2019s law,<\/span><\/p>\n

                                  P<\/span>total<\/span> = P<\/span>A<\/span>0<\/span>.X<\/span>A<\/span> + P<\/span>B<\/span>0<\/span>.X<\/span>B<\/span><\/p>\n

                                  X<\/span>A <\/span>= <\/span>3<\/span>5<\/span>, X<\/span>B <\/span>= <\/span>2<\/span>5<\/span><\/p>\n

                                  P<\/span>total<\/span> = 280 x <\/span>3<\/span>5<\/span> + 420 x <\/span>2<\/span>5<\/span><\/p>\n

                                  P<\/span>total<\/span> = 336 mm Hg<\/span><\/p>\n

                                  21. Urea responds with water to form A. A decomposes and forms B. B when passed through Cu2+ (aq), deep blue colour solution C is found. What is the compound C from the following<\/p>\n

                                    \n
                                  1. CuSO<\/span>4<\/span><\/li>\n
                                  2. [Cu(NH<\/span>3<\/span>)<\/span>4<\/span>]<\/span>2+<\/span><\/li>\n
                                  3. CuCO<\/span>3<\/span>.Cu(OH)<\/span>2<\/span><\/li>\n
                                  4. Cu(OH)<\/span>2<\/span><\/li>\n<\/ol>\n

                                    <\/b> The correct option is (b).<\/span><\/p>\n

                                    NH<\/span>2<\/span>CONH<\/span>2<\/span> + H<\/span>2<\/span>O \u2192 (NH<\/span>4<\/span>)<\/span>2<\/span>CO<\/span>3<\/span> \u21cb 2NH<\/span>3<\/span> + H<\/span>2<\/span>O + CO<\/span>2<\/span><\/p>\n

                                    4NH<\/span>3<\/span> + Cu<\/span>2+<\/span> (aq)\u00a0 \u2192 [Cu(NH<\/span>3<\/span>)<\/span>4<\/span>]<\/span>2+<\/span> (aq)<\/span><\/p>\n

                                    Here, Product A = (NH<\/span>4<\/span>)<\/span>2<\/span>CO<\/span>3<\/span><\/p>\n

                                    Product B = 2NH<\/span>3<\/span>\u00a0<\/span><\/p>\n

                                    The final product, C, is [Cu(NH<\/span>3<\/span>)<\/span>4<\/span>]<\/span>2+<\/span> (aq), which shows a deep blue colour.<\/span><\/p>\n

                                    22. Measuring zeta potential is useful in determining which property of colloidal solution?<\/p>\n

                                      \n
                                    1. Viscosity<\/span><\/li>\n
                                    2. Solubility<\/span><\/li>\n
                                    3. Size of the colloidal particles<\/span><\/li>\n
                                    4. Stability of the colloidal particles<\/span><\/li>\n<\/ol>\n

                                      <\/b> The correct option is (d).<\/span><\/p>\n

                                      Greater the zeta potential will be the stability of colloidal particles. There will be a balance in the middle of the repulsive interactions linking the charges of the electrical double layer and attractive Vander Waal interactions between molecules.<\/span><\/p>\n

                                      23. Identify the incorrect statement<\/p>\n

                                        \n
                                      1. The oxidation states of Cr in CrO<\/span>4<\/span>2-<\/span> and Cr<\/span>2<\/span>O<\/span>7<\/span>2-<\/span> are not the same.<\/span><\/li>\n
                                      2. The transition metals and their compounds are studied for their catalytic activity due to their capability to adopt multiple oxidation states and guise complexes.<\/span><\/li>\n
                                      3. Cr<\/span>2+<\/span> (d<\/span>4<\/span>) is a stronger reducing agent than Fe<\/span>2+<\/span> (d<\/span>6<\/span>) in water.<\/span><\/li>\n
                                      4. Interstitial compounds are formed when small atoms like C, H, or N are trapped inside the crystal lattices of matter.<\/span><\/li>\n<\/ol>\n

                                        <\/b>The correct option is (a).<\/span><\/p>\n

                                        Oxidation state of Cr in<\/span><\/p>\n

                                        CrO<\/span>4<\/span>2-<\/span> = +6<\/span><\/p>\n

                                        Cr<\/span>2<\/span>O<\/span>7<\/span>2-<\/span> = +6<\/span><\/p>\n

                                        Both are equal. Hence, all the statements are correct except (a).<\/span><\/p>\n

                                        Although the questions mentioned in the above articles are very few, many of them are repeated and important questions. Hopefully, these questions help you understand the questions’ tricks by analysing them. Otherwise, you can find the Aakash Institute nearby to get help from our experts.<\/span><\/p>\n

                                        Also See: NEET 2022 Answer Key with Solutions<\/a><\/p>\n

                                        FAQs About NEET 2022<\/a><\/h2>\n

                                        1. What are the critical topics of Chemistry for the NEET 2022 exam?<\/span><\/p>\n

                                        It is hard to say the important topics for the NEET 2022 exam. But, years of experience with Aakash have let their experts gain this knowledge. So, experts advised some chapters as important based on their weightage in the previous NEET exam. These chapters are given below:<\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n
                                        Chapter Name<\/b><\/td>\nWeightage<\/b><\/td>\n<\/tr>\n
                                        Chemistry in Everyday Life<\/span><\/td>\n4%<\/span><\/td>\n<\/tr>\n
                                        Alcohols, Phenols, and Ethers<\/span><\/td>\n8%<\/span><\/td>\n<\/tr>\n
                                        Coordination Compounds<\/span><\/td>\n4%<\/span><\/td>\n<\/tr>\n
                                        d- and f- Block Elements<\/span><\/td>\n4%<\/span><\/td>\n<\/tr>\n
                                        Electrochemistry<\/span><\/td>\n4%<\/span><\/td>\n<\/tr>\n
                                        Solutions<\/span><\/td>\n5%<\/span><\/td>\n<\/tr>\n
                                        Equilibrium<\/span><\/td>\n6%<\/span><\/td>\n<\/tr>\n
                                        Thermodynamics<\/span><\/td>\n9%<\/span><\/td>\n<\/tr>\n
                                        Chemical Bonding and Molecular Structure<\/span><\/td>\n5%<\/span><\/td>\n<\/tr>\n
                                        <\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

                                        2. What tips should I follow to practice the Chemistry syllabus for the NEET 2022?<\/p>\n

                                        You can follow the below tips:<\/p>\n