{"id":194102,"date":"2022-06-16T13:13:34","date_gmt":"2022-06-16T07:43:34","guid":{"rendered":"https:\/\/www.aakash.ac.in\/blog\/?p=194102"},"modified":"2023-05-02T12:55:01","modified_gmt":"2023-05-02T07:25:01","slug":"neet-chemistry-chapter-wise-important-questions","status":"publish","type":"post","link":"https:\/\/www.aakash.ac.in\/blog\/neet-chemistry-chapter-wise-important-questions\/","title":{"rendered":"NEET Chemistry Chapter-wise Important Questions"},"content":{"rendered":"

<\/a>NEET is less than two months away from you. It’s time to adopt the most effective ways to revise the <\/span>NEET syllabus <\/span>and important concepts of all three subjects. <\/span>Knowledge of <\/span>exam patterns<\/span>, syllabus structure of <\/span>Physics<\/span>, <\/span>Chemistry<\/span>, <\/span>Biology<\/span>, <\/span>mock papers<\/span>, and <\/span>dress code<\/span> is very important.<\/span><\/p>\n

This article will help you with chapter-wise important questions of Chemistry for NEET exam<\/a> preparations. Have a look.<\/span>
\n<\/a><\/p>\n

Chapter-Wise Important Questions for NEET Exam<\/a><\/h2>\n

Chapter 1: Some Basic Concepts of Chemistry<\/b><\/p>\n

1. What will be the normality of a solution obtained by mixing 0.45N and 0.60N NaOH in the ratio of 2:1 by volume?<\/p>\n

N = <\/span>N\u2081V\u2081 + N\u2082V\u2082<\/span>V\u2081 + V\u2082<\/span> = 0.5<\/span><\/p>\n

Therefore, the normality of the mixed solution is 0.5N.<\/span><\/p>\n

2. A measured temperature on the Fahrenheit scale is 200\u2109. What will be its value in \u2103?<\/span><\/p>\n

\u2109 = <\/span>9<\/span>5<\/span> \u2103 + 32<\/span><\/p>\n

200 = <\/span>9<\/span>5<\/span> \u2103 + 32<\/span><\/p>\n

Therefore, the temperature on the Celsius scale is 93.3\u2103.<\/span><\/p>\n

Chapter 2: Structure of Atom<\/b><\/p>\n

1. What is the total energy of the first orbit of an H-atom?<\/span><\/p>\n

Energy = – <\/span>2<\/span>\u00b3k\u00b2e\u2074m<\/span>h\u00b2<\/span><\/p>\n

2. What is the electronic configuration of Fe\u00b3\u207a?<\/p>\n

Fe\u00b3\u207a (23 electrons) = [Ar] 3d\u2075<\/span><\/p>\n

Chapter 3: Classification of Elements and Periodicity in Properties<\/b><\/p>\n

1. What are Eka-aluminium and Eka-silicon?<\/span><\/p>\n

Eka-aluminium is Gallium and Eka-silicon is Germanium.<\/span><\/p>\n

2. What elements from atomic numbers 58-71 are known?<\/span><\/p>\n

They are called Lanthanide series elements.<\/span><\/p>\n

Chapter 4: Chemical Bonding and Molecular Structure<\/b><\/p>\n

1. What is the most favourable condition for forming ionic bonds?<\/p>\n

Larger cation has lesser polarisation power, whereas smaller anion is less polarisable.<\/span><\/p>\n

2. Write the hybridization and shape of N(SiH\u2083)\u2083.<\/p>\n

The N-atom will donate its lone pair of electrons to the vacant d-orbital of Si. Therefore, it has sp\u00b2 hybridisation and planar shape.<\/span><\/p>\n

Chapter 5: States of Matter: Gases and Liquids<\/b><\/p>\n

1. If the temperature of an ideal gas is sealed, the rigid container is increased to 1.5 times the initial value (in K). What happens to its density?<\/p>\n

For a sealed rigid container, mass and volume remain the same. Hence, density will remain the same even if there is an increase in temperature.<\/span><\/p>\n

2. At low pressure, what will be Vander Waals’ equation for CH\u2084?<\/span><\/p>\n

Vander Waals\u2019 equation is<\/span><\/p>\n

(P + <\/span>a<\/span>V\u00b2<\/span>) (V – b) = RT<\/span><\/p>\n

At low P and high T, (V – b) = V<\/span><\/p>\n

Therefore, Vander Waals\u2019 equation for CH\u2084 will be PV = RT – <\/span>a<\/span>V<\/span> .<\/span><\/p>\n

Chapter 6: Thermodynamics<\/b><\/p>\n

1. What is the specific heat at constant pressure per gram of gas when its molar mass is M?<\/p>\n

Specific heat at constant pressure per gram, <\/span>C\u209a<\/span> = <\/span>R<\/span>M(<\/span>-1)<\/span>.<\/span><\/p>\n

2. When does the work done during the expansion of a gas depend on pressure?<\/p>\n

During isothermal expansion<\/span><\/p>\n

Work done = nRT log\u2091<\/span>V<\/span>f<\/span>V<\/span>i<\/span><\/p>\n

During adiabatic expansion<\/span><\/p>\n

Work done = <\/span>P\u2081V\u2081 – P\u2082V\u2082<\/span>-1<\/span><\/p>\n

In both cases, work done depends on pressure.<\/span><\/p>\n

Chapter 7: Equilibrium<\/b><\/p>\n

1. Which concept can explain the acidity of BF\u2083?<\/p>\n

According to the Lewis concept, a positive charge or an electron-deficient species act as Lewis acid. BF\u2083 is an electron-deficient compound, with B having only 6 electrons.<\/span><\/p>\n

2. What is the correct order of vapour pressure of water, acetone, and ether at 30\u2103?<\/p>\n

Greater the boiling point, the lesser the vapour pressure. Therefore, the correct order will be<\/span><\/p>\n

Ether > Acetone > Water<\/span><\/p>\n

Chapter 8: Redox Reactions<\/b><\/p>\n

1.3.92 g\/L of a sample of ferrous ammonium sulphate reacts completely with 50 mL N10 KMnO\u2084 solution. Calculate the percentage purity of the sample.<\/p>\n

N\u2081V\u2081 = N\u2082V\u2082<\/span><\/p>\n

N\u2081 x 1000 = <\/span>1<\/span>10<\/span> x 50<\/span><\/p>\n

N\u2081 = <\/span>1<\/span>200<\/span>\u00a0<\/span><\/p>\n

Equivalent weight of ferrous ammonium sulphate = molar weight = 392<\/span><\/p>\n

Strength of pure salt = 392 x <\/span>1<\/span>200<\/span>\u00a0 = 1.96 g\/L<\/span><\/p>\n

% purity = <\/span>1.96<\/span>3.92<\/span> x 100 = 50%<\/span><\/p>\n

Therefore, the percentage purity of the sample is 50%.<\/span><\/p>\n

2. Calculate the oxidation state of V in Rb\u2084Na[HV\u2081\u2080O\u2082\u2088].<\/p>\n

4 (+1) + (+1) + (+1) + 10x + 28 (-2) = 0<\/span><\/p>\n

x = +5<\/span><\/p>\n

Therefore, the oxidation state of V is +5.<\/span><\/p>\n

Chapter 9: Hydrogen<\/b><\/p>\n

1. What is semi-water gas?<\/span><\/p>\n

The mixture of CO, H\u2082, and N\u2082 is known as semi-water gas.<\/span><\/p>\n

2. Ordinary water is not used as a moderator in nuclear reactors. Why?<\/span><\/p>\n

Ordinary water absorbs too many neutrons to be used with unenriched natural uranium. Therefore, it affects the operation of such reactors and increases the overall cost.<\/span><\/p>\n

Chapter 10: s-block Elements<\/b><\/p>\n

1. Arrange the following ions in the increasing order of their \u2018Hydration Energy.\u2019<\/p>\n

Be\u00b2\u207a, Mg\u00b2\u207a, Ca\u00b2\u207a, Ba\u00b2\u207a, Si\u00b2\u207a<\/span><\/p>\n

Smaller the size of the cation, the higher the hydration energy. Therefore, the correct order is<\/span><\/p>\n

Ba\u00b2\u207a < Si\u00b2\u207a < Ca\u00b2\u207a < Mg\u00b2\u207a < Be\u00b2\u207a<\/span><\/p>\n

2. KO\u2082 is used in oxygen cylinders in space and submarines. Why?<\/p>\n

2KO\u2082 + 2H\u2082O \u2192 2KOH + H\u2082O\u2082 + O\u2082<\/span><\/p>\n

KO\u2082 is used as an oxidising agent. In space capsules, it is used as an air purifier. In submarines, it is used in breathing masks. These are all because it produces oxygen and removes carbon dioxide.<\/span><\/p>\n

Chapter 11: Organic Chemistry – Some Basic Principles and Techniques<\/b><\/p>\n

1. How many isomers of glucose are possible?<\/p>\n

Glucose has four dissimilar asymmetric carbon atoms. Hence, number of isomers = 2<\/span>4<\/span> = 16.<\/span><\/p>\n

2. What is the cause of resonance in a molecule?<\/p>\n

Resonance in a molecule arises due to the delocalisation of <\/span>-electrons.<\/span><\/p>\n

Chapter 12: Hydrocarbons<\/b><\/p>\n

1. What is the correct decreasing order of reactivity of alkenes towards given hydrogen halides propene, butene, and pentene?<\/p>\n

The reactivity of alkenes is inversely proportional to the number of carbon atoms. Therefore, the correct decreasing order is<\/span><\/p>\n

Propene > Butene > Pentene.<\/span><\/p>\n

2. 2-methyl propene is isomeric with but-1-ene. How can you distinguish them?<\/p>\n

Ozonolysis of these will give different products which can differentiate between but-1-ene and 2-methyl propene.<\/span><\/p>\n

Chapter 13: Environmental Chemistry<\/b><\/p>\n

1. What is the BOD value of clean water?<\/p>\n

BOD value is the amount of oxygen needed to decompose the organic material present in the water. For pure or clean water is <\/span> 5ppm.<\/span><\/p>\n

2. What are secondary pollutants?<\/p>\n

Secondary pollutants are not emitted directly from any source. They form by reacting with the molecules present in the atmosphere. Some secondary pollutants are nitric acid, PAN, etc.<\/span><\/p>\n

Chapter 14: Solid State<\/b><\/p>\n

1. At what angles for the first-order diffraction, spacing between two planes are and 2, respectively?<\/span><\/p>\n

n<\/span> = 2d sin<\/span><\/p>\n

In first case, n = 1, d = <\/span><\/p>\n

1 x <\/span> = 2d sin<\/span><\/p>\n

sin<\/span> = <\/span>1<\/span>2<\/span> = sin 30\u00b0<\/span><\/p>\n

= 30\u00b0<\/span><\/p>\n

In second case, n = 1, d = <\/span>2<\/span><\/p>\n

1 x <\/span>\u00a0 = 2 x <\/span>2<\/span> x sin<\/span><\/p>\n

sin<\/span> = 1 = sin 90\u00b0<\/span><\/p>\n

= 90\u00b0<\/span><\/p>\n

Therefore, the angles are 30\u00b0 and 90\u00b0.<\/span><\/p>\n

2. Which type of magnetic behaviour is shown by \u2018magnetite\u2019 (Fe3O4)?<\/p>\n

In Fe<\/span>3<\/span>O\u2084, iron and oxygen atoms are present in +5 and -2 ionic states. They are arranged in oppositely aligned magnetic moments. Irrespective of this, at room temperature, Fe<\/span>3<\/span>O\u2084 shows ferromagnetism due to different values of magnetic moments of both atoms.<\/span><\/p>\n

Chapter 15: Solutions<\/b><\/p>\n

1. What is the mathematical expression for Raoult\u2019s law?<\/p>\n

According to Raoult\u2019s law,<\/span><\/p>\n

P\u2070-P<\/span>P\u2070<\/span> = <\/span>n<\/span>n+N<\/span><\/p>\n

After simplifying it, <\/span>P\u2070-P<\/span>P\u2070<\/span> = <\/span>n<\/span>N<\/span>.<\/span><\/p>\n

2. 18g of glucose (C6H12O6) is added to 178.2g of water. What will be the vapour pressure of water for this aqueous solution at 100\u2103?<\/p>\n

Moles of glucose = <\/span>18<\/span>180<\/span> = 0.1<\/span><\/p>\n

Moles of water = <\/span>178.2<\/span>18<\/span> = 9.9<\/span><\/p>\n

Total mass = 0.1 + 9.9 = 10<\/span><\/p>\n

H\u2082O<\/span> = Mole fraction x Total pressure = <\/span>9.9<\/span>10<\/span> x 760 = 752.40<\/span><\/p>\n

Therefore, the vapour pressure of water for this aqueous solution at 100\u2103 is 752.40 Torr.<\/span><\/p>\n

Also Read:<\/strong><\/p>\n

NEET Chemistry Preparation: How To Prepare for NEET Chemistry Exam?<\/a>
\nNEET Chemistry Note-Making Tips That Actually Work<\/a>
\nHow to achieve excellent scores in NEET Chemistry?<\/a>
\nHow to Study Chemistry for NEET: Best Books & Preparation Tips<\/a><\/p>\n

Chapter 16: Electrochemistry<\/b><\/p>\n

1. Standard free energies of formation (in kJ\/mol) at 298 K are = -237.2, -394.4, and -8.2\u00a0 for H\u2082O (l), CO\u2082 (g), and pentane (g), respectively. What will be the value of Ecell\u2070 for the pentane-oxygen fuel cell?<\/p>\n

The balanced equation for pentane-oxygen cell reaction will be<\/span><\/p>\n

C\u2085H\u2081\u2082 + 8O\u2082 \u2192 5CO\u2082 + 6H\u2082O; n=32<\/span><\/p>\n

r<\/span> G\u2070<\/span>= [5 x <\/span>f<\/span> G\u2070<\/span>(CO\u2082) + 6 x <\/span>f<\/span> G\u2070<\/span>(6H\u2082O)] – [<\/span>f<\/span> G\u2070<\/span>(C\u2085H\u2081\u2082) + 8 x <\/span>f<\/span> G\u2070<\/span>(O\u2082)]<\/span><\/p>\n

r<\/span> G\u2070<\/span>= [5 x (-394.5) + 6 x (-237.2)] – [(-8.2) + 0] = -3387 kJ\/mol<\/span><\/p>\n

f<\/span> G\u2070<\/span>= -nF<\/span>E<\/span>cell<\/span>\u2070<\/span><\/p>\n

-3387000 = -32 x 96500 x <\/span>E<\/span>cell<\/span>\u2070<\/span><\/p>\n

E<\/span>cell<\/span>\u2070<\/span> = 1.0968 V<\/span><\/p>\n

Therefore, <\/span>E<\/span>cell<\/span>\u2070<\/span> for the pentane-oxygen fuel cell is 1.0968 V.<\/span><\/p>\n

2. What would be the product of electrolysis of molten ICl\u2083 is electrolysed?<\/span><\/p>\n

In the molten state, ICl\u2083 ionises as follows<\/span><\/p>\n

2ICl\u2083 \u2192 <\/span>ICl<\/span>2<\/span>+<\/span> + <\/span>ICl<\/span>4<\/span>–<\/span><\/p>\n

Therefore, both I\u2082 and Cl\u2082 are liberated at both electrodes.<\/span><\/p>\n

Chapter 17: Chemical Kinetics<\/b><\/p>\n

1. In the presence of a catalyst, what happens to the heat evolved or absorbed during the reaction?<\/p>\n

There is no effect on the heat evolved or absorbed during the reaction in the presence of a catalyst. It is because the catalyst does not participate in the reaction.<\/span><\/p>\n

2. Name the factor on which the value of the rate constant of the pseudo-first-order reaction depends.<\/span><\/p>\n

The value of the rate constant of the pseudo-first-order reaction depends on the concentration of reactants present in excess.<\/span><\/p>\n

Chapter 18: Surface Chemistry<\/b><\/p>\n

1. Which colligative property is used to determine the molar mass of a polymer?<\/p>\n

For the molar mass of a polymer, osmotic pressure is preferred because it is done at normal temperature. At higher temperatures, molecules are not stable.<\/span><\/p>\n

2. What happens to Brownian motion when the particle size of the dispersed phase increases in colloidal solution?<\/p>\n

Brownian movement is due to unequal bombardments of moving molecules of dispersion medium on colloidal particles. The bigger size of particles reduces the movement.<\/span><\/p>\n

Chapter 19: General Principles and Processes of Isolation of Elements<\/b><\/p>\n

1. What is the formula of Feldspar?<\/p>\n

Feldspar is K<\/span>2<\/span>O.Al<\/span>2<\/span>O<\/span>3<\/span>.6SiO<\/span>2<\/span>.<\/span><\/p>\n

2. You are given a mixture of ZnS and PbS. How will you separate them?<\/p>\n

The froth flotation process can separate the two compounds by adding NaCN. It is because ZnS forms soluble complexes while PbS forms forth.<\/span><\/p>\n

Chapter 20: p-Block Elements<\/b><\/p>\n

1. Arrange the boiling points of group 16 hydrides in increasing order.<\/p>\n

The boiling point depends upon the intermolecular forces of attraction. But, due to H-bonding in H<\/span>2<\/span>O molecules, its boiling point gets higher compared to others. Therefore, the correct order is<\/span><\/p>\n

H<\/span>2<\/span>S < H<\/span>2<\/span>Se < H<\/span>2<\/span>Te < H<\/span>2<\/span>O<\/span><\/p>\n

2. What is the correct order of Cl-O bond lengths in ClO\u207b, ClO\u2082\u207b, ClO\u2083\u207b, and ClO\u2084\u207b?<\/p>\n

The bond length of compounds is inversely proportional to bond order. Also, the greater the delocalisation of -electrons, the shorter the bond length. Therefore, the correct order is<\/span><\/p>\n

ClO\u2084\u207b < ClO\u2083\u207b < ClO\u2082\u207b < ClO\u207b<\/span><\/p>\n

Chapter 21: d- and f-Block Elements<\/b><\/p>\n

1. How many total rare earth elements are there?<\/span><\/p>\n

Lanthanides are known as rare earth elements. Therefore, there are a total of 14 rare earth elements.<\/span><\/p>\n

2. Arrange the decreasing order of the magnitude of the ionic radii of La3+, Ce3+, Yb3+, and Pm3+?<\/p>\n

Due to lanthanide contraction, ionic radii decrease. Hence, the order will be<\/span><\/p>\n

La<\/span>3+<\/span> > Ce<\/span>3+<\/span> > Pm<\/span>3+<\/span> > Yb<\/span>3+<\/span><\/p>\n

Chapter 22: Coordination Compounds<\/b><\/p>\n

1. Give the IUPAC name of K3[Al(C2O4)3].<\/p>\n

IUPAC name of K<\/span>3<\/span>[Al(C<\/span>2<\/span>O<\/span>4<\/span>)<\/span>3<\/span>] is potassium trioxalatoaluminate(III).<\/span><\/p>\n

2. Calculate the coordination number of Co in [Co(NH3)6]2+.<\/p>\n

The coordination number equals the total number of ligands in the compound. Hence, the coordination number of Co is 6.<\/span><\/p>\n

Chapter 23: Haloalkanes and Haloarenes<\/b><\/p>\n

1. An organic compound \u2018X\u2019 on treatment with Pyridinium Chlorochromate (PCC) in CH2Cl2 gives compound \u2018Y.\u2019 Compound \u2018Y\u2019 reacts with I2\/NaOH to form iodoform. Name the compound \u2018X.\u2019<\/p>\n

Compound \u2018X\u2019 will be CH<\/span>3<\/span>CH<\/span>2<\/span>OH.<\/span><\/p>\n

2. What will be the product of hydrolysis of 2-Bromo-3-methyl butane?<\/p>\n

It will be 2-methyl-2-butanol.<\/span><\/p>\n

Chapter 24: Alcohols, Phenols, and Ethers<\/b><\/p>\n

1. Write the correct order of acidic strength of the following compounds:<\/p>\n

Phenol, p-Cresol, m-Nitrophenol, p-Nitrophenol<\/span><\/p>\n

The acidity of a compound increases with the increase in electron-withdrawing groups and decreases with the increase in electron releasing groups. Hence, the order of acidic strength is<\/span><\/p>\n

p-Nitrophenol > m-Nitrophenol > Phenol > p-Cresol<\/span><\/p>\n

2. How will you distinguish between 1\u00b0 and 2\u00b0 alcohols?<\/p>\n

1\u00b0 and 2\u00b0 alcohols can be distinguished by Lucas reagent and Victor-Meyer Test. Also, 2\u00b0 alcohols can give a positive Iodoform test while 1\u00b0 cannot.<\/span><\/p>\n

Chapter 25: Aldehydes, Ketones, and Carboxylic Acids<\/b><\/p>\n

1. Name the reagent that reacts with both aldehyde and acetone easily.<\/p>\n

Grignard\u2019s reagent has carbanion as a nucleophile that can attack even at the carboxyl group of the ketone.<\/span><\/p>\n

2. Write the correct order of reactivity of PhCOPh, CH<\/span>3<\/span>CHO, and CH<\/span>3<\/span>COCh<\/span>3<\/span> with PhMgBr.<\/span><\/p>\n

The reactivity of carbonyl compounds with any nucleophile is based on the electrophilicity of carbonyl carbon and steric crowding around it. Hence, the correct order of reactivity is<\/span><\/p>\n

CH<\/span>3<\/span>CHO > CH<\/span>3<\/span>COCH<\/span>3<\/span> > PhCOPh<\/span><\/p>\n

Chapter 26: Organic Compounds Containing Nitrogen<\/b><\/p>\n

1. When a compound \u2018X\u2019 reacts with CHCl\u2083 in the presence of NaOH, a foul smell is formed. Name the reaction.<\/p>\n

When a compound \u2018X\u2019 reacts with CHCl\u2083 in the presence of NaOH, a foul-smelling gas \u2018isocyanide\u2019\u00a0 is formed. This gas, on further reduction, forms a secondary amine. It is a carbylamine reaction.<\/span><\/p>\n

2. How many carbon-containing primary amines will form when four carbon-containing primary amines react with Br and NaOH?<\/p>\n

When primary amines react with Br and NaOH, one carbon fewer results in animes being formed. It is a Hoffman-bromamide reaction. Therefore, this reaction will form three carbon-containing primary amines.<\/span><\/p>\n

Chapter 27: Biomolecules<\/b><\/p>\n

1. What is the principal role of PUFA?<\/p>\n

The fatty acids that contain more than one double bond in their backbone are known as Polyunsaturated Fatty Acids (PUFA). It supplies essential fatty acids and enhances atherosclerosis and cholesterol levels in the body.<\/span><\/p>\n

2. Name the elements Protistan shells and Sponge spicules made up of.<\/span><\/p>\n

Protistan shells and Sponge spicules are made up of Silica and Calcium.<\/span><\/p>\n

Chapter 28: Polymers<\/b><\/p>\n

1. Name the polymer that can absorb over 90% of its mass of water and doesn’t stick to wounds.<\/p>\n

Rayon.<\/span><\/p>\n

2. Give the characteristics of thermosetting polymers.<\/p>\n

They have heavily branched cross-linked polymers. And cannot reuse them.<\/span><\/p>\n

Chapter 29: Chemistry in Everyday Life<\/b><\/p>\n

1. What are Tranquillisers?<\/p>\n

Tranquillisers are substances that affect the central nervous system and induce sleep.<\/span><\/p>\n

2. When soap or detergent are added to the water, the surface tension of water is reduced by both. Why?<\/p>\n

When soap or detergent is added to the water, the ionic part of soap or detergent attracts grease. And repel water molecules. As a result, the hydrogen bonds that hold the water molecules get weakened. Therefore, the surface tension of water decreases.<\/span><\/p>\n

Also see:<\/b> NEET Chemistry: Chapter-wise Weightage & Important Topics<\/span><\/a><\/p>\n

Chemistry is the most scoring subject. With dedication and a little concentration, you can gain a strong grip on all the <\/span>important concepts<\/span><\/a> of <\/span>Chemistry<\/span><\/a>, <\/span>Physics<\/span><\/a>, and <\/span>Biology<\/span><\/a>. You can come and <\/span>look for us near you<\/span><\/a> to get an expert’s advice.<\/span><\/p>\n

FAQs about NEET Chemistry Chapter<\/h2>\n
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1. Are NCERT Chemistry Exemplar useful for NEET preparation?<\/h3>\n\t\t\t\t\t
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Yes. It is very useful. NCERT is counted as the best study material to prepare for national-level competitive exams. You can get many conceptual questions and chapter-wise exercises to practice more. The questions designed in NCERT Chemistry Exemplar are quite challenging and provide you with a platform to improve your knowledge.<\/p>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t\t\t\t\t

2. How does Aakash Institute help aspirants with Chemistry preparation for the NEET exam?<\/h3>\n\t\t\t\t\t
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At Aakash Institute, you will receive all the needed information and study materials for NEET preparation. It has the best team of Chemistry experts. They guide you through your whole journey till the NEET exam. And teach you all the best ways, tricks, and tips to their students.<\/p>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t\t\t\t\t

3. What is the design of the NEET Chemistry section?<\/h3>\n\t\t\t\t\t
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It is designed in such a way as to cover the syllabus of Classes 11 and 12, irrespective of the board. Whether you are a student of CBSE, ICSE, or any other board, you will find it fit to attempt the NEET exam paper. It makes the exam paper easy to hold, and you get easily familiar with it.<\/p>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t\t\t\t\t

4. How can I prepare for the NEET exam?<\/h3>\n\t\t\t\t\t
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For your NEET preparations, Aakash can proudly say that it is India's leading coaching institute for NEET preparations. According to your requirements, you have options like online classes, classroom coaching, distance learning classes, and even crash courses.<\/p>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

NEET is less than two months away from you. It’s time to adopt the most effective ways to revise the NEET syllabus and important concepts of all three subjects. Knowledge of exam patterns, syllabus structure of Physics, Chemistry, Biology, mock papers, and dress code is very important. This article will help you with chapter-wise important […]<\/p>\n","protected":false},"author":1,"featured_media":211193,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3716],"tags":[],"class_list":["post-194102","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-neet"],"yoast_head":"\nNEET Chemistry Chapter-wise Important Questions<\/title>\n<meta name=\"description\" content=\"This article will help you with NEET Chemistry chapter-wise important questions of Chemistry for NEET exam preparations.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.aakash.ac.in\/blog\/neet-chemistry-chapter-wise-important-questions\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta 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