{"id":153032,"date":"2022-04-28T16:30:17","date_gmt":"2022-04-28T11:00:17","guid":{"rendered":"https:\/\/www.aakash.ac.in\/blog\/?p=153032"},"modified":"2023-04-02T23:05:47","modified_gmt":"2023-04-02T17:35:47","slug":"ncert-concept-notes-for-cbse-class-12-mathematics-term-2-exams","status":"publish","type":"post","link":"https:\/\/www.aakash.ac.in\/blog\/ncert-concept-notes-for-cbse-class-12-mathematics-term-2-exams\/","title":{"rendered":"NCERT concept notes for CBSE Class 12 Mathematics Term 2 exams"},"content":{"rendered":"<p><span style=\"font-weight: 400;\">The time to test the preparations has reached. CBSE Class 10 and 12 Term 2 board exams have started. Students are in their full energised state. They are trying to prove their dedication by achieving an excellent score.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">June 7, 2022, is the <a href=\"https:\/\/www.aakash.ac.in\/boards\/cbse-class-12\" target=\"_blank\" rel=\"noopener\">CBSE Class 12<\/a> Term 2 Mathematics exam date. It is one of the major subjects for the Class 12 Science and Commerce stream students. Term 2 exams are going to be in subjective mode. Hence, there is a need to focus more on the revision.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Mathematics is an interesting and fun subject. But, students find themselves with an unknown fear towards it. Only practice is the thing that can reduce this fear in you and bring confidence in you. To help you build your confidence, we are here with the NCERT concepts notes for the <a href=\"https:\/\/www.aakash.ac.in\/boards\/cbse-class-12-syllabus\" target=\"_blank\" rel=\"noopener\">CBSE Class Term 2 Syllabus<\/a> Mathematics.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">This article will find all the important Mathematics notes of NCERT related to the <a href=\"https:\/\/www.aakash.ac.in\/blog\/cbse-class-12-term-2-maths-syllabus-exam-pattern-important-concepts\/\" target=\"_blank\" rel=\"noopener\">CBSE Class 12 Term 2 Maths syllabus<\/a>.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Did you know why every expert advises you to prepare from NCERT books? It is because CBSE mainly focuses on the NCERT syllabus, and other than this, NCERT textbooks and <\/span><a href=\"https:\/\/www.aakash.ac.in\/ncert-solutions\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">NCERT Solutions<\/span><\/a><span style=\"font-weight: 400;\"> themselves contain every required information for each topic. But, the student needs to give some extra attention to memorise them.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Before going through the notes of NCERT concepts, it is necessary to understand the syllabus and exam pattern of the Term 2 exam. Let\u2019s take a look at it first.<\/span><\/p>\n<h3>Syllabus &amp; Weightage Of Class 12 Term 2 Mathematics Exam 2022<\/h3>\n<p><span style=\"font-weight: 400;\">The latest updated syllabus of the <a href=\"https:\/\/www.aakash.ac.in\/blog\/10-days-revision-strategy-for-cbse-12th-maths-term-2-exam\/\" target=\"_blank\" rel=\"noopener\">Term 2 Mathematics exam 2022<\/a> for the Class 12 with the marking scheme is as follows:<\/span><\/p>\n<table>\n<tbody>\n<tr>\n<td><b>Unit Name<\/b><\/td>\n<td><b>Chapter Name<\/b><\/td>\n<td><b>Weightage<\/b><\/td>\n<\/tr>\n<tr>\n<td><span style=\"font-weight: 400;\">Calculus<\/span><\/td>\n<td>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Integrals<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Applications of Integrals<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Differential Equations<\/span><\/li>\n<\/ul>\n<\/td>\n<td><span style=\"font-weight: 400;\">18<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"font-weight: 400;\">Vector &amp; 3-D Geometry<\/span><\/td>\n<td>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Vectors<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Three-Dimensional Geometry<\/span><\/li>\n<\/ul>\n<\/td>\n<td><span style=\"font-weight: 400;\">14<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"font-weight: 400;\">Probability<\/span><\/td>\n<td>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Probability<\/span><\/li>\n<\/ul>\n<\/td>\n<td><span style=\"font-weight: 400;\">08<\/span><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><span style=\"font-weight: 400;\">Total<\/span><\/td>\n<td><span style=\"font-weight: 400;\">40<\/span><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><span style=\"font-weight: 400;\">Internal Assessment<\/span><\/td>\n<td><span style=\"font-weight: 400;\">10<\/span><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><b>Grand Total<\/b><\/td>\n<td><b>50<\/b><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h3>Exam Pattern Of Class 12 Term 2 Mathematics Exam 2022<\/h3>\n<p>The exam pattern for the Class 12 Term 2 Mathematics exam 2022 is as follows:<\/p>\n<table>\n<tbody>\n<tr>\n<td><b>Section<\/b><\/td>\n<td><b>Type Of Question<\/b><\/td>\n<td><b>Number Of Question<\/b><\/td>\n<td><b>Weightage<\/b><\/td>\n<\/tr>\n<tr>\n<td><span style=\"font-weight: 400;\">A<\/span><\/td>\n<td><span style=\"font-weight: 400;\">Short Answer Type Questions<\/span><\/td>\n<td><span style=\"font-weight: 400;\">6<\/span><\/td>\n<td><span style=\"font-weight: 400;\">12<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"font-weight: 400;\">B<\/span><\/td>\n<td><span style=\"font-weight: 400;\">Short Answer Type Questions<\/span><\/td>\n<td><span style=\"font-weight: 400;\">4<\/span><\/td>\n<td><span style=\"font-weight: 400;\">12<\/span><\/td>\n<\/tr>\n<tr>\n<td><span style=\"font-weight: 400;\">C<\/span><\/td>\n<td><span style=\"font-weight: 400;\">Long Answer Type Questions<\/span><\/td>\n<td><span style=\"font-weight: 400;\">4<\/span><\/td>\n<td><span style=\"font-weight: 400;\">16<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Also See: <a href=\"https:\/\/www.aakash.ac.in\/class-12-cbse-board-answers-solutions\" target=\"_blank\" rel=\"noopener\">CBSE Class 12 Answer Key 2022<\/a><\/p>\n<p><b>Chapter-Wise Notes Of Important Concepts Of Mathematics Based On NCERT For Class 12 Term 2 Board Exam<\/b><\/p>\n<p><span style=\"font-weight: 400;\">The notes of <a href=\"https:\/\/www.aakash.ac.in\/blog\/web-stories\/cbse-class-12-term-2-syllabus-maths-10-high-scoring-topics-for-cbse-maths-class-12-board-exam\/\" target=\"_blank\" rel=\"noopener\">Cbse Class 12 Maths important concepts<\/a> of each chapter are as follows:<\/span><\/p>\n<p><b>Chapter &#8211; Integral<\/b><\/p>\n<p><span style=\"font-weight: 400;\">Integration is the reverse process of differentiation.<\/span><\/p>\n<ul>\n<li aria-level=\"1\"><b>Some standard formulae of integration<\/b><\/li>\n<\/ul>\n<ol>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u222bx\u207f dx = (x\u207f\u207a\u00b9\/n+1) + C, n \u2260 -1<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u222b1\/x dx = log |x| + C<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u222b e\u02e3 dx =\u00a0 e\u02e3 + C<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u222b a\u02e3 dx = (a\u02e3\/log\u2091a) + C<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u222bsin x dx = -cos x + C<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u222bcos x dx = sin x + C<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u222bsec\u00b2x dx = tan x + C<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u222bcosec\u00b2x dx = -cot x + C<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u222bsec x tan x dx = sec x + C<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u222bcosec x cot x dx = -cosec x + C<\/span><\/li>\n<\/ol>\n<ul>\n<li aria-level=\"1\"><b>Methods of integration<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">There are five ways to solve integration.<\/span><\/p>\n<ol>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Integration by substitution<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Integration by parts<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Integration by partial fraction<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Integration using trigonometric identities<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Integration by a particular fraction<\/span><\/li>\n<\/ol>\n<ul>\n<li aria-level=\"1\"><b>Integration using partial fractions<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">We first resolve the denominator of the given fraction into the simplest factors. Based on these factors, we obtain the corresponding partial fractions.<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Definite integrals<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">Let F(x) be an antiderivative of <\/span><i><span style=\"font-weight: 400;\">f<\/span><\/i><span style=\"font-weight: 400;\">(x), then for any two values of the independent variable x, say a and b, the difference F(b) &#8211; F(a) is called the definite integral.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0\u222bf(x)dx = F(b)\u2212F(a), limit a\u2192b<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Properties Of definite integrals<\/b><\/li>\n<li aria-level=\"1\"><b>Definite integral as a limit of a sum<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">The definite integral \u222b x dx, with a limit a\u2192b of sum, is given by<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u222b x dx = [b\u00b2 &#8211; a\u00b2]\/2, limit a\u2192b<\/span><\/p>\n<h3>Chapter &#8211; Application of Integrals<b><\/b><\/h3>\n<ul>\n<li aria-level=\"1\"><b>Area under curves<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">Let y = f(x) be a continuous and finite function in [a,b]<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Area =\u00a0 \u222bf(x)dx = F(b)\u2212F(a), limit a\u2192b<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>The area bounded by two curves<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">Let f(x) and g(x) be continuous in [a,b] interval, then the area bounded by two curves is defined by,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Area =\u00a0 \u222b [f(x) &#8211; g(x)] dx, limit a\u2192b<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>The area bounded by a curve and a line<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">If the curve is defined as y = f(x) and line by y = g(x), then the area bounded by a curve and a line is defined as,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Area =\u00a0 \u222b [f(x) &#8211; g(x)] dx, limit a\u2192b<\/span><\/p>\n<p><b>Chapter &#8211; Differential Equation<\/b><\/p>\n<p><span style=\"font-weight: 400;\">An equation containing an independent variable, a dependent variable, and the derivatives of the dependent variable is called a differential equation.<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Differential equation formation<\/b><\/li>\n<\/ul>\n<p><b>Step 1:<\/b><span style=\"font-weight: 400;\"> Differentiate the equation of the given family of curves n times to get n more equations.<\/span><\/p>\n<p><b>Step 2:<\/b><span style=\"font-weight: 400;\"> Eliminate n constants using these (n+1) equations.<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Linear differential equation<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">The most general form of a linear differential equation is dy\/dx + Py = Q, where P is a constant and Q is a constant or a function of x.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">(dy\/dx) + Py = Q<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Homogeneous differential equation<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">An equation of the form dy\/dx = f(x,y)\/g(x,y), where both f(x,y) and g(x,y) are homogeneous functions of degree n, is called homogeneous differential equation.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">dy\/dx = (x\u00b2<\/span><span style=\"font-weight: 400;\">-y\u00b2)\/xy<\/span><\/p>\n<h3>Chapter &#8211; Vectors<\/h3>\n<p><span style=\"font-weight: 400;\">A definite magnitude and definite directions specify vector quantities.<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Product of vectors<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">Vector Product:\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The scalar product of vectors is solved by using this formula:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Scalar Product:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">We can express the scalar product as:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">a.b=|a||b| cos\u03b8<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Laws of vectors<\/b><\/li>\n<\/ul>\n<ol>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Vector addition is commutative.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Vector addition is associative.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Vector addition shows the existence of additive identity.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The additive inverse also exists in vector addition.<\/span><\/li>\n<\/ol>\n<h3>Chapter &#8211; Three &#8211; dimensional Geometry<b><\/b><\/h3>\n<ul>\n<li aria-level=\"1\"><b>Direction cosine and direction ratios<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">Direction cosines of a line:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">If a line makes angles , , with the x-axis, y-axis, and z-axis, respectively,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Then,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">l\u00a0 = cos , m = cos , n = cos <\/span><\/p>\n<p><span style=\"font-weight: 400;\">are called the direction cosines.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Direction ratios of a line:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Any three numbers a, b, c, proportion to the direction cosines l, m, n respectively of a line, are called the direction ratios of the line.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Then,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Direction ratios = l\/a = m\/b = n\/c<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Cartesian equation of a line<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">Cartesian equation:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The equations of a line passing through two given points, A(x\u2081, y\u2081, z\u2081) and B(x\u2082, y\u2082, z\u2082), are given by<\/span><\/p>\n<p><span style=\"font-weight: 400;\">(x-x\u2081)\/(x\u2082-x\u2081) = (y-y\u2081)\/(y\u2082-y\u2081) = (z-z\u2081)\/(z\u2082-z\u2081)<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Distance between two lines<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">If you have two parallel lines<\/span><\/p>\n<p><span style=\"font-weight: 400;\">r = a\u2081 +b and r = a\u2082 +b<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Then,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The shortest distance between them is given by [ | a\u2082 &#8211; a\u2081 | x b] \/ |b|<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Distance between a point and a plane<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">If there is a point P (x\u2080, y\u2080, z\u2080) and a plane Q with the equation Ax+By+Cz = D.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Then,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The distance between P and Q is given by<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Distance = [ |Ax\u2080 + By\u2080 +Cz\u2080 + D| ] \/ \u221a (A\u00b2 + B\u00b2 + C\u00b2)<\/span><\/p>\n<h3>Chapter &#8211; Probability<\/h3>\n<p><span style=\"font-weight: 400;\">This unit is based on the multiplication theorem on probability for independent events and conditional probability.<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Multiplication theorem of probability<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">If A and B are two events of a sample space such that<\/span><\/p>\n<p><span style=\"font-weight: 400;\">P(A) \u2260 0 and P(B) \u2260 0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Then,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">P(A\u2229B) = P(A) * P(B\/A) = P(B) * (PA\/B)<\/span><b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Bayes\u2019 Theorem<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">Bayes&#8217; theorem is stated mathematically as the following equation:<\/span><br \/>\n<b><\/b><\/p>\n<ul>\n<li aria-level=\"1\"><b>Binomial distribution<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">Where,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Conditions for binomial distribution:<\/span><\/p>\n<ol>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The experiment is performed for a finite and fixed number of trials.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Each trial must give either a success or a failure.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The probability of success in each trial is the same.<\/span><\/li>\n<\/ol>\n<ul>\n<li aria-level=\"1\"><b>Random variable and its probability distribution<\/b><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">The probability distribution of a random variable X is defined only when<\/span><\/p>\n<ol>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Each p\u2097 &gt;= 0<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">\u2211p\u2097 = 1<\/span><\/li>\n<\/ol>\n<h3>Conclusion<\/h3>\n<p><span style=\"font-weight: 400;\">Mathematics asks for practice, and it is hard to achieve an excellent score in this exam without practice. Due to the new examination pattern from earlier, you have more chances to perform better than previous batches\u2019 students.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">If you find the fear of Mathematics, you only have to do one thing, i.e., go through <\/span><a href=\"https:\/\/www.aakash.ac.in\/ncert-solutions\/class-12\/maths\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">NCERT Solutions for Class 12 Mathematics<\/span><\/a><span style=\"font-weight: 400;\"> and books and revise from there. Do you believe that preparation from NCERT books advances you in scoring best in your board exams and helps you with competitive exams like JEE, NEET, CUET, and other exams syllabus at the same time?<\/span><\/p>\n<p><span style=\"font-weight: 400;\">We hope the above-detailed information and concepts notes will help you boost your CBSE Class 12 Term 2 Mathematics exam 2022 score.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Wish you all the best!<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>The time to test the preparations has reached. CBSE Class 10 and 12 Term 2 board exams have started. Students are in their full energised state. They are trying to prove their dedication by achieving an excellent score. June 7, 2022, is the CBSE Class 12 Term 2 Mathematics exam date. It is one of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":126721,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3581],"tags":[2795,2126],"class_list":["post-153032","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cbse","tag-cbse-class-12-mathematics","tag-cbse-term-2"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>CBSE Class 12 Maths Notes: NCERT concept notes for CBSE Class 12 Mathematics Term 2 exams 2022<\/title>\n<meta name=\"description\" content=\"CBSE Class 12 Maths Trem 2 Exam 2022: Check out all the important Mathematics notes of NCERT related to the Class 12 Term 2 syllabus, chapter wise weightage and more on aakash.ac.in\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, 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