{"id":140092,"date":"2022-12-26T13:45:22","date_gmt":"2022-12-26T08:15:22","guid":{"rendered":"https:\/\/www.aakash.ac.in\/blog\/?p=140092"},"modified":"2023-03-25T23:23:56","modified_gmt":"2023-03-25T17:53:56","slug":"what-is-ohms-law-explanation-from-cbse-class-12-physics-syllabus","status":"publish","type":"post","link":"https:\/\/www.aakash.ac.in\/blog\/what-is-ohms-law-explanation-from-cbse-class-12-physics-syllabus\/","title":{"rendered":"What is Ohm&#8217;s Law? Explanation from CBSE Class 12 Physics Syllabus"},"content":{"rendered":"<p><span style=\"font-weight: 400;\">Ohm\u2019s law is an important concept to learn from the chapter on electricity in Physics. Here the law has been explained in detail for your understanding to feel confident solving questions regarding this topic. Laws like such are important from the <a href=\"https:\/\/www.aakash.ac.in\/jee-main-exam\" target=\"_blank\" rel=\"noopener\">JEE Main 2023<\/a> point of view. If you find physics a tough nut to crack, <\/span><a href=\"https:\/\/www.aakash.ac.in\/our-centres\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">Find Aakash Coaching Institute Near You<\/span><\/a><span style=\"font-weight: 400;\"> so that you can attend face-to-face classes.<\/span><\/p>\n<h2>Ohm\u2019s Law<\/h2>\n<p><span style=\"font-weight: 400;\"><a href=\"https:\/\/www.aakash.ac.in\/important-concepts\/physics\/ohms-law\" target=\"_blank\" rel=\"noopener\">Ohm\u2019s Law<\/a> is named after the German physicist George Ohm, as he was the first person to prove this law experimentally.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">George Simon Ohm established the relation between electric current and potential difference. Ohm\u2019s law states, \u201cPotential applied across the end of the conductor is directly proportional to the current flowing through a conductor, provided the physical conditions (such as temperature) remain unchanged.\u2019\u2019<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0V\u00a0 \u00a0 =\u00a0 \u00a0 IR or I\u00a0 =\u00a0 V\/R,<\/span><\/p>\n<p><span style=\"font-weight: 400;\">where R is the constant of proportionality called resistance of the circuit<\/span><\/p>\n<p><span style=\"font-weight: 400;\">I in the current in amperes<\/span><\/p>\n<p><span style=\"font-weight: 400;\">V is the voltage across the conductor in volts.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">From the above formula, it is clear that current is inversely proportional to resistance. If resistance is doubled, the current is halved, and if the resistance is halved, the current is doubled. If understanding this law is tricky for you, check <\/span><a href=\"https:\/\/www.aakash.ac.in\/ncert-solutions\/class-12\/physics\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">NCERT Solutions for Class 12 Physics<\/span><\/a><span style=\"font-weight: 400;\"> and <\/span><a href=\"https:\/\/www.aakash.ac.in\/ncert-solutions\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">NCERT Solutions<\/span><\/a><span style=\"font-weight: 400;\">. It will help you a lot. Check <\/span><a href=\"https:\/\/www.aakash.ac.in\/ncert-solutions\/class-12\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">NCERT Solutions for Class 12<\/span><\/a><span style=\"font-weight: 400;\"> if you want to learn other subjects. Ohm\u2019s Law is a reliable relation that describes the conductivity of many electrically conductive materials. However, some materials do not follow Ohm\u2019s Law. Those are called non-ohmic. Examples are diodes.<\/span><\/p>\n<h2>An Experimental Analogy to Understand the Concept of Ohm\u2019s Law<\/h2>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Let us take a beaker filled with water.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Let us make three holes in the beaker vertically and attach three water pipes to the holes so that water flows through them from the beaker to the outside.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">We find that the water flowing through the uppermost water pipe is high, the flow of water through the middle water pipe is relatively lower, and the speed of the water flowing through the lowermost water pipe is the lowest.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Also, we notice that the uppermost water pipe is lying closest to the beaker; the middle one is a little farther away, while the lowermost water pipe lies farthest away from the beaker.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The water adjacent to the uppermost pipe is the uppermost layer, so its pressure is low. The water adjacent to the middle water pipe has one layer above it so its pressure is higher. The water adjacent to the lowermost water pipe has two layers of water, so the pressure is the highest. So, the pressure in the three water layers is different. This pressure difference resulted in a speed difference.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Water always travels from a higher concentration to a lower concentration, that is, against a concentration gradient. That is why the water moves from inside to outside the beaker. The pressure of water outside the beaker is 0 Pascal.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Suppose the water pressure in layer one is 5 Pascal, the pressure of water in the next layer is 10 Pascal, and the pressure of water in the third layer is 15 Pascal.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Let\u2019s compare the pressure difference of the first layer of water with the pressure outside the beaker. It will come out to be equal to 5 Pa (5-0), the pressure difference for the next layer comes out to be 10 Pa (10-0), and the pressure difference for the lowermost layer comes out to be 15 Pa (15-0).<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">From this discussion, we conclude that the more the pressure difference, the more the speed of water flow.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The same rule is followed by airflow. It always moves from a high-pressure gradient to a lower-pressure gradient. If the pressure difference between the two points through which airflow is high, the speed of air increases.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">To understand Ohm\u2019s Law through this analogy, let us substitute the flow of water from the beaker with the flow of current, the pressure difference with the potential difference. So we can say that the more the potential difference, the more the flow of current. The more the difference in the voltage of two conductors, the more the speed of electric current flows through them. So, voltage is directly proportional to current and inversely proportional to resistance. More the resistance, the slower the current flows.<\/span><\/li>\n<\/ul>\n<h2>Ohmic and Non-Ohmic Conductors<\/h2>\n<p><span style=\"font-weight: 400;\">Based on whether or not conductors follow Ohm\u2019s Law, they can be divided into two types:<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Ohmic conductors<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Non-ohmic conductors<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Ohmic conductors: Those conductors that follow Ohm\u2019s Law, provided the physical conditions such as temperature remain constant are called ohmic conductors. A perfect example of an ohmic conductor is a transistor. Some more examples are metals like silver, copper, and aluminum. The VI graph of ohmic conductors is linear.\u00a0<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Non-ohmic conductors: These conductors have their unique characteristics, due to which they do not follow Ohm\u2019s Law. Examples of non-ohmic conductors are diodes. Graphically speaking, the slope of the current and voltage is a curved line for non-ohmic conductors, unlike ohmic conductors, where it is straight.<\/span><\/li>\n<\/ul>\n<h2>Limitations of Ohm\u2019s Law<\/h2>\n<ol>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">It does not apply to non-ohmic circuits.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Even inside ohmic circuits, there are some limitations of this law. For example, suppose a large current flows through a conductor, according to H=I\u00b2RT. In that case, heating takes place due to which the resistance of the conductor also increases and because of high resistance, instead of getting a straight line, we get a curve.\u00a0<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The temperature and physical state of the material has to remain constant to fulfil Ohm\u2019s Law.<\/span><\/li>\n<\/ol>\n<p><span style=\"font-weight: 400;\">Therefore, Ohm\u2019s Law is not universal.<\/span><\/p>\n<h2>VI Graph of Ohm\u2019s Law<\/h2>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The graph between the potential difference V and the corresponding current I is a straight line, passing through the origin for ohmic (metal) conduction.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The current I is directly proportional to the potential difference V and inversely proportional to the resistance. The current flows through a conductor slower if the resistance is high.<\/span><\/li>\n<\/ul>\n<p>Visit our web story to get a detailed understanding of<a href=\"https:\/\/www.aakash.ac.in\/blog\/web-stories\/15-important-laws-of-physics-for-iit-jee-exam-preparation\/\" target=\"_blank\" rel=\"noopener\"> Ohm&#8217;s Law.<\/a><\/p>\n<h2>Conclusion<\/h2>\n<p><span style=\"font-weight: 400;\">If you are studying Physics for Class 12th, you will likely be planning to compete in the JEE Main examination shortly. If you start preparing for competitive exams at the right time, you will have a headstart and better qualify for them. Get yourself acquainted with the JEE Main 2023 Exam pattern and JEE Main 2023 Syllabus by checking <\/span><a href=\"https:\/\/www.aakash.ac.in\/jee-main-exam-pattern\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">JEE Main Exam Pattern<\/span><\/a><span style=\"font-weight: 400;\"> and <\/span><a href=\"https:\/\/www.aakash.ac.in\/jee-main-syllabus\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">JEE Main Syllabus<\/span><\/a><span style=\"font-weight: 400;\"> to stay ahead of the game.\u00a0\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Preparing for a competitive exam can be challenging; only the smartest survive. Work hard starting from now itself and set your dream score. Keep an eye on JEE Main 2023 Result and JEE Main 2023 Counselling here <\/span><a href=\"https:\/\/www.aakash.ac.in\/jee-main-counselling\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">JEE Main Counselling<\/span><\/a><span style=\"font-weight: 400;\"> to get acquainted with the process. Also, ask for JEE Main 2023 preparation tips and JEE Main 2023 Important Chapters from your seniors and use the knowledge to your advantage. You can also check JEE Main 2023 Rankings and watch interviews of the toppers to get additional tips.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">In case you don\u2019t want to miss &#8211; All the necessary information regarding JEE Main 2023, like JEE Main 2023 Notification, JEE Main 2023 Registration process, JEE Main 2023 Registration Date, JEE Main 2023 Eligibility Criteria, JEE Main 2023 Application Form, have been provided here <\/span><a href=\"https:\/\/www.aakash.ac.in\/jee-main-application-form\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">JEE Main Application Form<\/span><\/a><span style=\"font-weight: 400;\">, <\/span><a href=\"https:\/\/www.aakash.ac.in\/jee-main-important-dates\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">JEE Main Important Dates<\/span><\/a><span style=\"font-weight: 400;\">, <\/span><a href=\"https:\/\/www.aakash.ac.in\/jee-main-eligibility-criteria\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">JEE Main Eligibility Criteria<\/span><\/a><span style=\"font-weight: 400;\"> for your reference if it is your goal to attend this competitive exam.<\/span><\/p>\n<p>Visit the important concept page to know about <a href=\"https:\/\/www.aakash.ac.in\/important-concepts\/physics\/ohms-law\" target=\"_blank\" rel=\"noopener\">Ohm&#8217;s law<\/a> in detail.<\/p>\n<h2>FAQs<\/h2>\n\t\t<div class=\"wp-faq-schema-wrap\">\n\t\t\t\t\t\t<div class=\"wp-faq-schema-items\">\n\t\t\t\t\t\t\t\t\t<h3>1. What is Ohm\u2019s Law and its formula?<\/h3>\n\t\t\t\t\t<div class=\"\">\n\t\t\t\t\t\t<p>Ohm\u2019s Law is a fundamental law of electricity establishing a relationship between three fundamental elements of Physics: voltage, current, and potential difference. It states that the voltage or potential difference between two points is directly proportional to the current passing through the resistance and inversely proportional to the resistance of the circuit. The formula for Ohm\u2019s Law is V=IR.<\/p>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t\t\t\t\t<h3>2. What questions can be asked about this topic in JEE 2023?<\/h3>\n\t\t\t\t\t<div class=\"\">\n\t\t\t\t\t\t<p>JEE examination contains an objective type of questions. They give you four options, from which you must select the best answer. As far as physics is concerned, there will be 30 questions in total, out of which 20 will be multiple choice questions, while the remaining ten will be non-MCQs with numerical value as an option. You should, therefore, memorize the formulas very well like \u201cV=IR\u201d as you can solve numerical-based questions with their help.<\/p>\n<p>Also, they ask examples of ohmic\/non-ohmic conductors in the form of multiple-choice questions. You can go through JEE Main Previous Year Question Papers here, JEE Previous Year Questions, to get acquainted with the question\u2019s pattern. Also, check JEE Main Mock Tests and JEE Main Physics Syllabus to get an idea of the pattern of questions and the syllabus. Also, checking out Important Concepts might help you in this regard. If you fulfil the JEE Main 2023 Eligibility Criteria and compete in JEE Main 2023, keep track of JEE Main 2023 Registration Date and JEE Main 2023 Form to fill it up at the right time.\u00a0<\/p>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t\t\t\t\t<h3>3. What are the three elements of Ohm\u2019s Law?<\/h3>\n\t\t\t\t\t<div class=\"\">\n\t\t\t\t\t\t<p>Ohms\u2019 Law is an empirical and basic law of electricity that states that \u201c Potential applied across the end of the conductor is directly proportional to the current flowing through a conductor, provided the physical conditions (such as temperature) remain unchanged.\u2019\u2019The three elements of Ohm\u2019s Law are current, voltage and resistance. According to this law, if we increase the resistance across the conductor, the current flowing through it decreases and vice-versa.<\/p>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t\t\t\t\t<h3>4. Is Ohm\u2019s Law important for JEE Main 2023?<\/h3>\n\t\t\t\t\t<div class=\"\">\n\t\t\t\t\t\t<p>Ohm\u2019s Law is a fundamental law of Physics. As Physics is an integral part of JEE 2023, studying this law and understanding its concepts is important for the exam.<\/p>\n<p>Memorize the formulas well. It will help you solve most of the numerical-based questions. Ohm\u2019s Law is important because it establishes a relationship between three fundamental elements of electricity voltage, current, and resistance.<\/p>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t\t\t\t\t<h3>5. Do all conductors follow Ohm\u2019s Law?<\/h3>\n\t\t\t\t\t<div class=\"\">\n\t\t\t\t\t\t<p>No, all conductors do not follow Ohm\u2019s Law. Such kinds of conductors are called non-ohmic conductors. Semiconductors like diodes and transistors have their characteristics and are examples of non-ohmic conductors. Even if you vary the current, a diode provides a nearly constant voltage drop, so it does not follow Ohm\u2019s Law. The VI graph of such conductors is non-linear. Ohm\u2019s Law, therefore, is not universal.<\/p>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t\t\t<\/div>\n\t\t<\/div>\n\t\t\n","protected":false},"excerpt":{"rendered":"<p>Ohm\u2019s law is an important concept to learn from the chapter on electricity in Physics. Here the law has been explained in detail for your understanding to feel confident solving questions regarding this topic. Laws like such are important from the JEE Main 2023 point of view. If you find physics a tough nut to [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":138139,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3581],"tags":[2120,2878,2126,2606],"class_list":["post-140092","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cbse","tag-cbse-class-12","tag-cbse-class-12-physics","tag-cbse-term-2","tag-cbse-term-2-exams"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Explain the Ohm&#039;s Law From CBSE Class 12 Physics syllabus<\/title>\n<meta name=\"description\" content=\"Know more about Ohm&#039;s law and detailed analysis of Ohm&#039;s law from CBSE Class 12 Physics notes\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" 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