{"id":132673,"date":"2022-04-04T16:57:52","date_gmt":"2022-04-04T11:27:52","guid":{"rendered":"https:\/\/www.aakash.ac.in\/blog\/?p=132673"},"modified":"2023-04-11T00:08:32","modified_gmt":"2023-04-10T18:38:32","slug":"arithmetic-progression-cbse-10th-maths-important-concepts","status":"publish","type":"post","link":"https:\/\/www.aakash.ac.in\/blog\/arithmetic-progression-cbse-10th-maths-important-concepts\/","title":{"rendered":"Arithmetic Progression CBSE 10th Maths: Important Concepts"},"content":{"rendered":"<p><span style=\"font-weight: 400;\">We all observe particular patterns in our daily lives. Like, the number of petals in a rose flower, the design of scales on a fish, the shape of a pine cone, etc. If we implement such patterns in mathematics, they are known as progressions. A progression is considered a series or sequence of integers that abide by a particular pattern. There are three types of mathematical progressions: Arithmetic Progression, Geometric Progression, and Harmonic Progression. We shall learn all the <\/span><a href=\"https:\/\/www.aakash.ac.in\/important-concepts\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">important concepts<\/span><\/a><span style=\"font-weight: 400;\"> of Arithmetic Progression in this article.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The distance between the steps of a ladder is in arithmetic progression. Arithmetic progression or arithmetic sequence is a set of integers in which the difference between any two numbers is always the same. The difference between two integers in an arithmetic progression is a common difference. It is represented by the lowercase letter &#8216;d.&#8217; The students must understand that arithmetic progression occurs when the numbers in a list increase or decrease by a constant common difference. Arithmetic progression is a crucial topic as many day-to-day problems are solved using it. Direct questions related to arithmetic progressions are asked in the <a href=\"https:\/\/www.aakash.ac.in\/jee-main-exam\" target=\"_blank\" rel=\"noopener\">JEE Main 2022 Exam<\/a>.<\/span><\/p>\n<p>Understand the arithmetic progression as a ladder with ten rungs (footholds). The space between two rungs is the same from bottom to top. The area between the first and second rung equals the distance between the second and third rung, and so on. The uniform area in the ladder is the common difference &#8216;d&#8217;.<\/p>\n<h3>\u00a0Identifying Arithmetic Progressions<\/h3>\n<p><span style=\"font-weight: 400;\">In many books, arithmetic progression is abbreviated as &#8216;AP&#8217;. &#8216;AP&#8217; is also the standard acronym for representing arithmetic progressions. In the CBSE 10th Maths, students will often find this abbreviation instead of the entire term. The students must realise that the question is an arithmetic progression and solve it accordingly.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0Given below are some series that follows arithmetic progression:<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">0, 3, 6, 9, 12, \u2026\u2026<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">4, 2, 1, 0, -2, \u2026..<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">x, x + 5, x + 10, x + 15, \u2026..<\/span><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">\u00a0Are they all in an arithmetic progression? Below is a detailed series description of which series is in AP and which isn&#8217;t.\u00a0<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The first series 0, 3, 6, 9, 12, \u2026\u2026 follows a pattern. That pattern can be determined by using the concept of common differences. First, finding the difference between the first two terms, we get (3 &#8211; 0) = 3. Next, finding the difference between the second and third terms, we get (6 &#8211; 3) = 3. Going on in the same manner 9 &#8211; 6 = 3, 12 &#8211; 9 = 3. Hence, there is a constant difference between each term of this series. Thus, 0, 3, 6, 9, 12, \u2026\u2026 is an arithmetic progression.\u00a0<\/span><\/li>\n<\/ul>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">Following the same procedure for the second series 4, 2, 1, 0, -2, \u2026\u2026 The common difference between first and second terms is (2 &#8211; 4) = -2. (1 &#8211; 2) = -1 is the difference between the second and third terms of the series. Thus there are two different values for the common difference. Hence, this series is not in arithmetic progression.<\/span><\/li>\n<\/ul>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400;\">The third series is algebraic. The students are often confused about determining the AP of an algebraic series. No matter what variable is in the series, the series will be an AP if the difference is constant.\u00a0<\/span><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">\u00a0In the series x, x + 5, x + 10, x + 15<\/span><\/p>\n<p><span style=\"font-weight: 400;\">(x + 5) &#8211; x = 5<\/span><\/p>\n<p><span style=\"font-weight: 400;\">(x + 10) &#8211; ( x + 5) = x + 10 &#8211; x &#8211; 5 = 5<\/span><\/p>\n<p><span style=\"font-weight: 400;\">(x + 15) &#8211; ( x + 10) = x + 15 &#8211; x &#8211; 10 = 5<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0Since the common difference of &#8216;5&#8217; is prominent in the series, this progression is an AP.\u00a0<\/span><\/p>\n<h3>\u00a0Finding the Common Difference between an AP<\/h3>\n<p><span style=\"font-weight: 400;\">The common difference plays a very important role in determining whether a series is an AP or not. It is calculated by subtraction of consecutive terms. If there are two terms &#8216;x&#8217; and &#8216;y&#8217; written as (x, y) in a series, then the common difference will be (y &#8211; x). For example, the sequence given below is an AP.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0k, l, m, n, o, \u2026\u2026.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The common difference will either be (l &#8211; k), (m &#8211; l), (n &#8211; m), or (o &#8211; n). The second term of the series is subtracted from the first term irrespective of the type of AP. If the series is increasing, then the common difference is positive. Otherwise, if the series is a decreasing series, the common difference is negative. If the common difference is 0, it is not considered an AP.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0<\/span><b>Example: <\/b><span style=\"font-weight: 400;\">Find the common difference between the series 10, 7, 4, 1<\/span><\/p>\n<p><b>Ans:<\/b><span style=\"font-weight: 400;\"> The series 10, 7, 4, and 1 is a decreasing series. Hence, the common difference will be negative.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d = (7 &#8211; 10) = -3\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0or<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d = (4 &#8211; 7) = -3<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Since the common difference is constant, the series is an AP.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0The converse of the statement mentioned above is also true. If the common difference between the terms of an AP is a positive integer, then the series will be increasing. Otherwise, if the common distinction between the terms of an AP is a negative integer, the series will be a decreasing series.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0Remember to always subtract consecutive numbers. The common difference is not attained if a student removes the third term of the series from the first term. Common differences will be found when any term is subtracted with its consecutive succeeding term. Don&#8217;t subtract any term with its preceding term.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0Looking at the pattern the common difference is formulated as:\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">AP \u2192 n <\/span><span style=\"font-weight: 400;\">a-1<\/span><span style=\"font-weight: 400;\"> , n <\/span><span style=\"font-weight: 400;\">a<\/span><span style=\"font-weight: 400;\"> , n <\/span><span style=\"font-weight: 400;\">a+1<\/span><span style=\"font-weight: 400;\"> , n <\/span><span style=\"font-weight: 400;\">a + 2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">d = ( n <\/span><span style=\"font-weight: 400;\">a<\/span><span style=\"font-weight: 400;\"> &#8211; n <\/span><span style=\"font-weight: 400;\">a-1<\/span><span style=\"font-weight: 400;\">), where \u2018n\u2019 refers to the term and \u2018a\u2019 = 2, 3, 4, 5, \u2026&#8230;<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0<\/span><b>How To Make an AP?<\/b><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0The students must follow the below-mentioned steps to make an AP.<\/span><\/p>\n<p><b>Step 1:<\/b><span style=\"font-weight: 400;\"> Choose an integer that will serve as the AP&#8217;s first term. This will be the starting number.\u00a0<\/span><\/p>\n<p><b>Step 2: <\/b><span style=\"font-weight: 400;\">To get the second term, fix a common difference and start adding or subtracting from the first term.<\/span><\/p>\n<p><b>Step 3: <\/b><span style=\"font-weight: 400;\">To acquire the third term, add or subtract the common difference from the second term.<\/span><\/p>\n<p><b>Step 4: <\/b><span style=\"font-weight: 400;\">Steps 1-3 must be repeated to get to the nth term and obtain the necessary AP.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0Many times questions related to the formation of AP have appeared in <\/span><a href=\"https:\/\/byjus.com\/jee-mock-test\"><span style=\"font-weight: 400;\">JEE Main Mock Tests<\/span> <span style=\"font-weight: 400;\">2022 <\/span><\/a><span style=\"font-weight: 400;\">\u00a0and <\/span><a href=\"https:\/\/www.aakash.ac.in\/jee-advanced-exam\"><span style=\"font-weight: 400;\">JEE Advanced 2022 Exam<\/span><\/a><span style=\"font-weight: 400;\">. The students must learn the steps mentioned above by heart.\u00a0<\/span><\/p>\n<h3><span style=\"font-weight: 400;\">\u00a0<\/span>Arithmetic Sequence Formula<\/h3>\n<p><span style=\"font-weight: 400;\">\u00a0All the rudimentary concepts of AP have been discussed so far. The students must now be confident in the basics of AP. The <\/span><a href=\"https:\/\/www.aakash.ac.in\/important-concepts\/maths\"><span style=\"font-weight: 400;\">maths concepts<\/span><\/a><span style=\"font-weight: 400;\"> and formulas learnt above will help the students understand the arithmetic sequence formula, which is given as:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0<\/span><b>For increasing series:<\/b><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0a, a + d, a + 2d, a + 3d, \u2026\u2026\u2026\u2026\u2026., a + (k &#8211; 1)d.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0Here &#8216;a&#8217; is known as the first term of the AP, and &#8216;d&#8217;, as discussed above, is the common difference between consecutive terms. (k &#8211; 1) is the final term of the AP, and k = {set of whole numbers}<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0<\/span><b>For decreasing series:<\/b><span style=\"font-weight: 400;\">\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">a, a &#8211; d, a &#8211; 2d, a &#8211; 3d, \u2026\u2026\u2026\u2026\u2026., a &#8211; (k &#8211; 1)d. The terminology remains the same as written above.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0If a student is provided with the initial term and the common difference &#8216;d&#8217; of an AP, then they can evaluate the value of any term of that AP. The below-mentioned formula is called the explicit formula for arithmetic progression and is formulated as\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">L = a + (k &#8211; 1)d<\/span><\/p>\n<h3>\u00a0Sum of Arithmetic Sequence<\/h3>\n<p><span style=\"font-weight: 400;\">The sum of an arithmetic progression is the last but very important topic. Questions related to the sum of AP have appeared a lot of times in CBSE 10th Maths papers. There are two dominant formulas for determining the sum of series having &#8216;n&#8217; number of terms. They are given as\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0Sn = n\/2 [ 2a + (n &#8211; 1) d ]<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0And<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0Sn = n\/2 [ a (1 + n) ]<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0Here, Sn refers to the sum of the series having &#8216;n&#8217; terms, &#8216;a&#8217; is the first term of the series, and &#8216;d&#8217; is a common difference.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0There are two approaches to finding the sum of an arithmetic sequence. If a student knows the first and last terms of the AP, they can use the second formula to determine the sum directly. But, if the students are provided with the nth term, they have to use the first method to obtain the sum.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0<\/span><b>Example:<\/b><span style=\"font-weight: 400;\"> Find the sum of arithmetic sequence -1, 1, 3, 5, &#8230; up to the first 22 terms.<\/span><\/p>\n<p><b>Solution:<\/b><span style=\"font-weight: 400;\"> Given\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">First term a = -1<\/span><\/p>\n<p><span style=\"font-weight: 400;\">n = 22<\/span><\/p>\n<p><span style=\"font-weight: 400;\">d = (1 &#8211; (-1)) = 1 + 1 = 2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0<\/span><span style=\"font-weight: 400;\">Using the first formula: S22 = n\/2 [ 2a + (n &#8211; 1) d ]<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0S22 = 22\/2 [ (2 x -1) + (22 &#8211; 1) x 2 ]<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0S22 = 11 x [ (-2) + (21) x 2 ]<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0S22 = 11 x [ (-2) + 42 ]<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0S22 = 11 x [ 40 ]<\/span><\/p>\n<p><span style=\"font-weight: 400;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0S22 = 440<\/span><\/p>\n<p><b>\u00a0<\/b><\/p>\n<p><b>Answer:<\/b><span style=\"font-weight: 400;\"> The sum of the -1, 1, 3, 5, &#8230; up to the first 22 terms is 850.<\/span><\/p>\n<h3>Conclusion<\/h3>\n<p><span style=\"font-weight: 400;\">Arithmetic progression is crucial for the class 10 CBSE board examination. It also serves a decent role in competitive exams like JEE 2022 and other <\/span><a href=\"https:\/\/www.aakash.ac.in\/olympiads-gateway-global-recognition\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\">olympiads<\/span><\/a><span style=\"font-weight: 400;\">. The only thing a student needs to remember about arithmetic progression is that it is a series whose pattern is based on the addition or subtraction of common differences. Continuous addition or subtraction of common difference &#8216;d&#8217; in the terms will lead to the formation of arithmetic series. The students can extend an AP to infinity. That concludes all the concepts related to arithmetic progression. After studying this article, a student can easily solve numerical and word problems present in<\/span><a href=\"https:\/\/www.aakash.ac.in\/ncert-solutions\" target=\"_blank\" rel=\"noopener\"><span style=\"font-weight: 400;\"> NCERT Solutions.\u00a0<\/span><\/a><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>We all observe particular patterns in our daily lives. Like, the number of petals in a rose flower, the design of scales on a fish, the shape of a pine cone, etc. If we implement such patterns in mathematics, they are known as progressions. A progression is considered a series or sequence of integers that [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":132692,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3719],"tags":[2323,1568,2686],"class_list":["post-132673","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-jee","tag-cbse-2022","tag-cbse-class-10","tag-cbse-class-10-term-2"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Arithmetic Progression CBSE 10th Maths: Important Concepts<\/title>\n<meta name=\"description\" content=\"Arithmetic progression is a crucial topic as many day-to-day problems are solved using it. 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