By Team Aakash Byju's | 13th November 2022
The correct answer is D. C–I, C–Br, C–Cl, C–F.
Brief Explanation
Bond enthalpy defines the amount of energy stored in a bond between atoms in a molecule.
Bond dissociation enthalpy increases as bond multiplicity decreases.
Unpaired Valence Electrons
Sharing of Available Valence Electrons
Atom 1
Atom 2
Covalent Molecule
The high bond length in C-I results in lower bond strength and bond dissociation enthalpy.
135
177
194
214
C-F
C-Cl
C-Br
C-I
Length
C-X Bond
C-F has a high bond dissociation enthalpy due to its short bond length.
C-Br
C-Cl
C-F
270
240
C-I
330
450
Bond dissociation enthalpies /KJ mol-1
C-X Bond
As a result, the bond dissociation enthalpies are in the following order: C−I<C−Br<C−Cl<C−F.
C-Br
C-Cl
C-F
270
240
C-I
330
450
Bond dissociation enthalpies /KJ mol-1
C-X Bond