When Are the Diagonals of a Trapezium Equal?

By Team Aakash Byju's | 31st January 2023

In given figure, ABCD is a trapezium with AB||DC. If AED is similar to BEC, prove that  AD = BC.

We must note 2 things: (i) Corresponding sides of two similar triangles are in equal proportion. (ii) If 2 corresponding angles in two triangles measure the same, then the triangles are similar.

Given, ΔAED∼ΔBEC,

=>

AE

BE

=

ED

EC

AD

BC

=

Consider triangles ΔABE and ΔCDE,

∠AEB=∠CED

∠EAB=∠ECD

(vertically oppsoite angles)

(alternate angles)

Thus, ΔABE∼ΔCDE by AA-similarity.

=>

CD

=

EB

ED

AE

EC

AB

=>

ED

EC

=

EB

AE

Further, because ΔAED∼ΔBEC gives

=>

BE

=

EC

ED

AE

EB

AE

and ΔABE∼ΔCDE gives

ED

EC

=

EB

AE

= 1

Since,

=>

=

AE

EB

AD = BC

AE

BE

ED

EC

=

AD

BC

and

= 1