By Team Aakash Byju's | 16th January 2023
The electric field inside the surface and on it is zero
All charges must necessarily be outside the surface
The electric field inside the surface is necessarily uniform
All the above
Detailed Explanation
In the given equation, E is the electric field and ds is the small surface vector.
The integration of dot product ∮ E . ds represents the flux.
ds
ds
E
θ
Since, it is given that ∮ E . ds = 0
Also, we know that ∮ E . ds =
Where q is the charge enclosed by the surface and ε is the constant.
S
q
ε
0
0
Thus , when ∮ E . ds = 0 , q= 0
So, the net charge enclosed by the surface S must be zero. So if any charges exist, they must be outside of the surface.
Thus, option B is correct.