By Team Aakash Byju's | 1st January 2023
8 × 10 N
A straight conductor carries a current of 5 A. An electron travelling with a 10 ms parallel to the wire at a distance of 0.1 m from the conductor, experiences a force of
6
-1
-20
3.3 × 10 N
-19
8 × 10 N
-18
1.6 × 10 N
-19
Detailed Explanation
-18
The magnitude of the magnetic field produced in the given case will be perpendicular to the electron's motion.
Therefore,
where, B is the magnetic field i is the current carrying in the conductor a is the distance between the wire and the conductor
Also ,
B =
4 π
µ
a
2i
.
4 π
µ
=
-7
10
B =
4 π
µ
a
2i
.
0
0
I
Current
B
MagneticField
0
Using the given values in the formula for the magnetic field we get,
B =
Wb
m
0.1
×
-5
10
-7
10
2 × 5
=
2
The expression for the force on the electron is given by,
F = qvB
where , q is the charge on electron v is the velocity of electron B is magnetic field
Thus the force experienced by the electron is
F = (1.6 × 10 ) × 5 × 10 ×10
-5
-18
= 8 × 10 N
6
-19