# How to Find Distance Between 2 Bodies Using Equation of Motion?

By Team Aakash Byju's | 31st January 2023

2v  t+       gt

## D

Two bodies are thrown simultaneously from a tower with the same initial velocity v0 one vertically upwards, the other vertically downwards. The distance between the two bodies after time t is.

-1

o

2

1

2

2v  t

o

v  t+       gt

o

1

2

v  t

o

Detailed Explanation

### The correct answer is  option B . 2v  t

o

Given that one body is thrown vertically upwards & another body is thrown vertically downwards from a tower of height say h with the same initial velocity v  .

Let s  be the distance of the body from the tower which is thrown upward and s  be the distance of the body from the tower which is thrown downward.

1

2

v

v

o

o

2

1

g

Thus distance between two bodies  is:

=> s =s  +s

1

2

From the second equation of motion, we can write

v  t-       gt

o

1

2

v  t+       gt

o

1

2

s =

1

s =

2

For vertically upward motion

2

2

For vertically downward motion

Total distance covered in t sec

=> s =s  +s

1

2

= 2v  t

o

.  .

.