By Team Aakash Byju's | 30th December 2022

A

32166.3 C

B

C

D

The Charge Required to Deposit  9g of Al from an Al   Solution is:

96500 C

3216.33 C

9650 C

3+

Detailed Explanation

The correct answer is  option B) 96500 C.

Arrow

The reaction is  Al   +3e   →Al.

3+

-

Aluminium

The atomic mass of  Al=27 g/mol.

9g of Al=

=0.333 moles.

27

9

1 mole Al= 3 moles electrons.

Moles of  elements(n)

Atoms of  elements(N)

Mass of  elements(m)

n : Number of Moles

m : Mass

M : Molar Mass

N : Number of Atoms

N   : Avogadro's number (6.022 × 10    )

A

23

 0.333 moles Al = 0.333×3                                            = 1 mole electrons.

1 mole electrons =1 faraday                                of electricity

=96500 C.

Faraday's Law