By Team Aakash Byju's | 2nd December 2022
A tangent galvanometer has a coil of 50 turns and a radius of 20 cm. The horizontal component of the earth's field is 3×10 T. Find the current through the coil.
0.5 A
0.39 A
0.29 A
0.19 A
A.
B.
C.
D.
-5
Detailed Explanation
We are asked to find the current through the coil in a tangent galvanometer due to which there is a deflection of 45.
0
Given,
B = 3×10
H
-5
T
,
n = 50 turns,
r = 20 cm = 20×10 m.
-2
The formula to be used is:
I =
2rB tanθ
H
µ n
0
Let us consider the deflection is 45° so that tan θ = tan 45° = 1.
=> I =
2 × 20 × 10
-2
× 3 × 10
-5
50 × 4π × 10
-7
(∵ µ =4π × 10 )
-7
=> I =
0.19 A
(∵ π =
22
7
)
0