By Team Aakash Byju's | 29th December 2022

Calculation of Heat Discharged and Efficiency

A heat engine operating between 227 deg C and 27 deg C absorbs 1 kcal of heat from the 227 deg C reservoir per cycle.

(Question Continues)

The amount of heat discharged into the low-temperature reservoir.

The amount of work done/cycle.

The efficiency of the cycle.

 Calculate

(Question Continues)

The options are:

A

B

C

D

0.4 kcal, 0.6 kcal, 40%

0.6 kcal, 0.4 kcal, 40%

0.4 kcal, 0.6 kcal, 60%

0.7 kcal, 0.4 kcal, 40%

Detailed Explanation

The correct answer is  A) 0.4 kcal, 0.6 kcal, 40%.

Arrow

T′=227+273=500 K T=27+273=300 K q′=1 kcal

Calculation of Work Done:

w

q

'

=

T - T

'

'

w

=

q

(

T - T

'

'

)

Calculation of Work Done:

'

Putting the various values in the reaction

w

=

1

(

500 - 300

)

500 

w

=

(

500 

200

)

w=0.4 kcal.

Calculation of heat discharged q

q′−q=w 1−q=0.4 q=0.6 kcal.

Calculation of Efficiency:

η=q′w =0.4 kcal or 40%